| Exam Board | AQA |
| Module | Further Paper 2 (Further Paper 2) |
| Year | 2024 |
| Session | June |
| Marks | 1 |
| Topic | Simple Harmonic Motion |
2 The movement of a particle is described by the simple harmonic equation
$$\ddot { x } = - 25 x$$
where \(x\) metres is the displacement of the particle at time \(t\) seconds, and \(\ddot { x } \mathrm {~m} \mathrm {~s} ^ { - 2 }\) is the acceleration of the particle.
The maximum displacement of the particle is 9 metres.
Find the maximum speed of the particle.
Circle your answer.
[0pt]
[1 mark]
\(15 \mathrm {~m} \mathrm {~s} ^ { - 1 }\)
\(45 \mathrm {~m} \mathrm {~s} ^ { - 1 }\)
\(75 \mathrm {~m} \mathrm {~s} ^ { - 1 }\)
\(135 \mathrm {~m} \mathrm {~s} ^ { - 1 }\)