AQA Further AS Paper 2 Statistics 2018 June — Question 2 1 marks

Exam BoardAQA
ModuleFurther AS Paper 2 Statistics (Further AS Paper 2 Statistics)
Year2018
SessionJune
Marks1
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPoisson distribution
TypeSingle time period probability
DifficultyModerate -0.8 This is a straightforward Poisson probability calculation requiring only the complement rule and basic formula application. Students need to calculate P(Y>1) = 1 - P(Y≤1) = 1 - [P(Y=0) + P(Y=1)] using the standard Poisson formula with λ=3. The multiple-choice format and single calculation step make this easier than average, though it's from Further Maths so the baseline is slightly higher.
Spec5.02j Poisson formula: P(X=x) = e^(-lambda)*lambda^x/x!5.02k Calculate Poisson probabilities

2 The discrete random variable \(Y\) has a Poisson distribution with mean 3 Find the value of \(\mathrm { P } ( Y > 1 )\) to three significant figures.
Circle your answer. \(0.149 \quad 0.199 \quad 0.801 \quad 0.950\)

Question 2:
AnswerMarks Guidance
AnswerMarks Guidance
\(0.801\)B1 Circles correct answer
Total: 1
## Question 2:

| Answer | Marks | Guidance |
|--------|-------|----------|
| $0.801$ | B1 | Circles correct answer |
| **Total: 1** | | |

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2 The discrete random variable $Y$ has a Poisson distribution with mean 3

Find the value of $\mathrm { P } ( Y > 1 )$ to three significant figures.\\
Circle your answer.\\
$0.149 \quad 0.199 \quad 0.801 \quad 0.950$

\hfill \mbox{\textit{AQA Further AS Paper 2 Statistics 2018 Q2 [1]}}