| Exam Board | AQA |
| Module | Further AS Paper 2 Statistics (Further AS Paper 2 Statistics) |
| Year | 2018 |
| Session | June |
| Topic | Continuous Probability Distributions and Random Variables |
| Type | Calculate probability P(X in interval) |
1 Let \(X\) be a continuous random variable with probability density function given by
$$f ( x ) = \begin{cases} \frac { 3 } { 4 } x ( 2 - x ) & 0 \leq x \leq 2
0 & \text { otherwise } \end{cases}$$
Find \(\mathrm { P } ( X = 1 )\)
Circle your answer.
0
\(\frac { 1 } { 2 }\)
\(\frac { 3 } { 4 }\)
\(\frac { 27 } { 32 }\)