| Exam Board | AQA |
| Module | Paper 1 (Paper 1) |
| Year | 2021 |
| Session | June |
| Topic | Trig Equations |
8
- Given that
$$9 \sin ^ { 2 } \theta + \sin 2 \theta = 8$$
show that
$$8 \cot ^ { 2 } \theta - 2 \cot \theta - 1 = 0$$
8
- Hence, solve
$$9 \sin ^ { 2 } \theta + \sin 2 \theta = 8$$
in the interval \(0 < \theta < 2 \pi\)
Give your answers to two decimal places.
8 - Solve
$$9 \sin ^ { 2 } \left( 2 x - \frac { \pi } { 4 } \right) + \sin \left( 4 x - \frac { \pi } { 2 } \right) = 8$$
in the interval \(0 < x < \frac { \pi } { 2 }\)
Give your answers to one decimal place.