AQA Paper 1 2021 June — Question 1 1 marks

Exam BoardAQA
ModulePaper 1 (Paper 1)
Year2021
SessionJune
Marks1
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicInequalities
TypeSolve quadratic inequality
DifficultyEasy -1.8 This is a straightforward quadratic inequality requiring only identification of critical points (-7/2 and 3) and determining which regions satisfy the inequality, presented as a multiple-choice question requiring minimal working. Significantly easier than average A-level questions.
Spec1.02g Inequalities: linear and quadratic in single variable1.02h Express solutions: using 'and', 'or', set and interval notation
1 State the set of values of \(x\) which satisfies the inequality $$( x - 3 ) ( 2 x + 7 ) > 0$$ Tick ( \(\checkmark\) ) one box. $$\begin{aligned} & \left\{ x : - \frac { 7 } { 2 } < x < 3 \right\} \\ & \left\{ x : x < - 3 \text { or } x > \frac { 7 } { 2 } \right\} \\ & \left\{ x : x < - \frac { 7 } { 2 } \text { or } x > 3 \right\} \\ & \left\{ x : - 3 < x < \frac { 7 } { 2 } \right\} \end{aligned}$$
Question 1:
AnswerMarks Guidance
\(\left\{x: x < -\frac{7}{2} \text{ or } x > 3\right\}\)B1 Ticks the correct box; AO1.1b 
## Question 1:

$\left\{x: x < -\frac{7}{2} \text{ or } x > 3\right\}$ | B1 | Ticks the correct box; AO1.1b

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1 State the set of values of $x$ which satisfies the inequality

$$( x - 3 ) ( 2 x + 7 ) > 0$$

Tick ( $\checkmark$ ) one box.

$$\begin{aligned}
& \left\{ x : - \frac { 7 } { 2 } < x < 3 \right\} \\
& \left\{ x : x < - 3 \text { or } x > \frac { 7 } { 2 } \right\} \\
& \left\{ x : x < - \frac { 7 } { 2 } \text { or } x > 3 \right\} \\
& \left\{ x : - 3 < x < \frac { 7 } { 2 } \right\}
\end{aligned}$$

\hfill \mbox{\textit{AQA Paper 1 2021 Q1 [1]}}
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Q1 1 Q2 1 Q3 1 Q4 1 Q5 6 Q6 7 Q7 7 Q8 9 Q9 15 Q10 8 Q11 8 Q12 8 Q13 8 Q14 10 Q15 10