2 The daily costs, in pounds, for five managers A, B, C, D and E to travel to five different centres are recorded in the table below.
| A | B | C | D | E |
| Centre 1 | 10 | 11 | 8 | 12 | 5 |
| Centre 2 | 11 | 5 | 11 | 6 | 7 |
| Centre 3 | 12 | 8 | 7 | 11 | 4 |
| Centre 4 | 10 | 9 | 14 | 10 | 6 |
| Centre 5 | 9 | 9 | 7 | 8 | 9 |
Using the Hungarian algorithm, each of the five managers is to be allocated to a different centre so that the overall total travel cost is minimised.
- By reducing the rows first and then the columns, show that the new table of values is
| 3 | 6 | 3 | 6 | 0 |
| 4 | 0 | 6 | 0 | 2 |
| 6 | 4 | 3 | 6 | 0 |
| 2 | 3 | 8 | 3 | 0 |
| 0 | 2 | 0 | 0 | 2 |
- Show that the zeros in the table in part (a) can be covered with three lines and use adjustments to produce a table where five lines are required to cover the zeros.
- Hence find the two possible ways of allocating the five managers to the five centres with the least possible total travel cost.
- Find the value of this minimum daily total travel cost.