AQA FP2 2007 January — Question 6 12 marks

Exam BoardAQA
ModuleFP2 (Further Pure Mathematics 2)
Year2007
SessionJanuary
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComplex numbers 2
TypeRoots of unity with trigonometric identities
DifficultyStandard +0.8 This is a multi-part Further Maths question requiring cube roots of unity, algebraic manipulation using the key identity 1+ω+ω²=0, and culminating in a trigonometric identity proof. While parts (a)-(b) are standard FP2 material, part (c)(iii) requires insight to connect the simplified expressions to Euler's formula and extract the cosine form. The extended chain of reasoning and the non-routine final step elevate this above average difficulty.
Spec4.02n Euler's formula: e^(i*theta) = cos(theta) + i*sin(theta)4.02r nth roots: of complex numbers

6
  1. Find the three roots of \(z ^ { 3 } = 1\), giving the non-real roots in the form \(\mathrm { e } ^ { \mathrm { i } \theta }\), where \(- \pi < \theta \leqslant \pi\).
  2. Given that \(\omega\) is one of the non-real roots of \(z ^ { 3 } = 1\), show that $$1 + \omega + \omega ^ { 2 } = 0$$
  3. By using the result in part (b), or otherwise, show that:
    1. \(\frac { \omega } { \omega + 1 } = - \frac { 1 } { \omega }\);
    2. \(\frac { \omega ^ { 2 } } { \omega ^ { 2 } + 1 } = - \omega\);
    3. \(\left( \frac { \omega } { \omega + 1 } \right) ^ { k } + \left( \frac { \omega ^ { 2 } } { \omega ^ { 2 } + 1 } \right) ^ { k } = ( - 1 ) ^ { k } 2 \cos \frac { 2 } { 3 } k \pi\), where \(k\) is an integer.

6
\begin{enumerate}[label=(\alph*)]
\item Find the three roots of $z ^ { 3 } = 1$, giving the non-real roots in the form $\mathrm { e } ^ { \mathrm { i } \theta }$, where $- \pi < \theta \leqslant \pi$.
\item Given that $\omega$ is one of the non-real roots of $z ^ { 3 } = 1$, show that

$$1 + \omega + \omega ^ { 2 } = 0$$
\item By using the result in part (b), or otherwise, show that:
\begin{enumerate}[label=(\roman*)]
\item $\frac { \omega } { \omega + 1 } = - \frac { 1 } { \omega }$;
\item $\frac { \omega ^ { 2 } } { \omega ^ { 2 } + 1 } = - \omega$;
\item $\left( \frac { \omega } { \omega + 1 } \right) ^ { k } + \left( \frac { \omega ^ { 2 } } { \omega ^ { 2 } + 1 } \right) ^ { k } = ( - 1 ) ^ { k } 2 \cos \frac { 2 } { 3 } k \pi$, where $k$ is an integer.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{AQA FP2 2007 Q6 [12]}}