AQA FP1 2008 January — Question 1 4 marks

Exam BoardAQA
ModuleFP1 (Further Pure Mathematics 1)
Year2008
SessionJanuary
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComplex Numbers Arithmetic
TypeReal and imaginary part expressions
DifficultyModerate -0.8 This is a straightforward Further Maths question requiring only basic complex number operations: finding a conjugate, performing scalar multiplication and addition, then equating real and imaginary parts. It's routine manipulation with no problem-solving insight needed, though being FP1 places it slightly above typical Core content.
Spec4.02a Complex numbers: real/imaginary parts, modulus, argument4.02e Arithmetic of complex numbers: add, subtract, multiply, divide

1 It is given that \(z _ { 1 } = 2 + \mathrm { i }\) and that \(z _ { 1 } { } ^ { * }\) is the complex conjugate of \(z _ { 1 }\).
Find the real numbers \(x\) and \(y\) such that $$x + 3 \mathrm { i } y = z _ { 1 } + 4 \mathrm { i } z _ { 1 } *$$

Question 1:
AnswerMarks Guidance
Working/AnswerMarks Guidance
\(z_1 + 4i\,z_1^* = (2+i) + 4i(2-i)\)M1 Use of conjugate
\(= (2+i) + (8i+4)\)M1 Use of \(i^2 = -1\)
\(= 6 + 9i\), so \(x = 6\) and \(y = 3\)M1A1 M1 for equating real and imaginary parts
Total4
## Question 1:

| Working/Answer | Marks | Guidance |
|---|---|---|
| $z_1 + 4i\,z_1^* = (2+i) + 4i(2-i)$ | M1 | Use of conjugate |
| $= (2+i) + (8i+4)$ | M1 | Use of $i^2 = -1$ |
| $= 6 + 9i$, so $x = 6$ and $y = 3$ | M1A1 | M1 for equating real and imaginary parts |
| **Total** | **4** | |

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1 It is given that $z _ { 1 } = 2 + \mathrm { i }$ and that $z _ { 1 } { } ^ { * }$ is the complex conjugate of $z _ { 1 }$.\\
Find the real numbers $x$ and $y$ such that

$$x + 3 \mathrm { i } y = z _ { 1 } + 4 \mathrm { i } z _ { 1 } *$$

\hfill \mbox{\textit{AQA FP1 2008 Q1 [4]}}