AQA FP1 2008 January — Question 3 5 marks

Exam BoardAQA
ModuleFP1 (Further Pure Mathematics 1)
Year2008
SessionJanuary
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStandard trigonometric equations
TypeGeneral solution — find all solutions
DifficultyModerate -0.8 This is a straightforward trig equation requiring only a substitution and knowledge that tan θ = 1 when θ = π/4 + nπ. The question involves routine manipulation with no problem-solving insight needed, making it easier than average despite being Further Maths content.
Spec1.05o Trigonometric equations: solve in given intervals

3 Find the general solution of the equation $$\tan 4 \left( x - \frac { \pi } { 8 } \right) = 1$$ giving your answer in terms of \(\pi\).

Question 3:
AnswerMarks Guidance
Working/AnswerMarks Guidance
Use of \(\tan\frac{\pi}{4} = 1\)B1 Degrees or decimals penalised in last mark only
Introduction of \(n\pi\)M1 or \(kn\) at any stage
Division of all terms by 4m1
Addition of \(\frac{\pi}{8}\)m1 OE
GS \(x = \frac{3\pi}{16} + \frac{n\pi}{4}\)A1 OE
Total5
## Question 3:

| Working/Answer | Marks | Guidance |
|---|---|---|
| Use of $\tan\frac{\pi}{4} = 1$ | B1 | Degrees or decimals penalised in last mark only |
| Introduction of $n\pi$ | M1 | or $kn$ at any stage |
| Division of all terms by 4 | m1 | |
| Addition of $\frac{\pi}{8}$ | m1 | OE |
| GS $x = \frac{3\pi}{16} + \frac{n\pi}{4}$ | A1 | OE |
| **Total** | **5** | |

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3 Find the general solution of the equation

$$\tan 4 \left( x - \frac { \pi } { 8 } \right) = 1$$

giving your answer in terms of $\pi$.

\hfill \mbox{\textit{AQA FP1 2008 Q3 [5]}}