AQA FP1 2008 January — Question 5 8 marks

Exam BoardAQA
ModuleFP1 (Further Pure Mathematics 1)
Year2008
SessionJanuary
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicConic sections
TypeConic translation and transformation
DifficultyStandard +0.3 This is a straightforward Further Maths question on hyperbolas requiring basic recall of asymptote equations, substitution to find coordinates, and applying a simple translation. All parts are routine applications of standard techniques with no problem-solving insight needed, though it's slightly above average difficulty due to being FP1 content rather than core A-level.
Spec1.02n Sketch curves: simple equations including polynomials1.02w Graph transformations: simple transformations of f(x)1.02x Combinations of transformations: multiple transformations

5 The diagram shows the hyperbola $$\frac { x ^ { 2 } } { 4 } - y ^ { 2 } = 1$$ and its asymptotes. \includegraphics[max width=\textwidth, alt={}, center]{a0a30197-ca11-40d9-9ccd-30281c5e0fb4-03_531_1013_616_516}
  1. Write down the equations of the two asymptotes.
  2. The points on the hyperbola for which \(x = 4\) are denoted by \(A\) and \(B\). Find, in surd form, the \(y\)-coordinates of \(A\) and \(B\).
  3. The hyperbola and its asymptotes are translated by two units in the positive \(y\) direction. Write down:
    1. the \(y\)-coordinates of the image points of \(A\) and \(B\) under this translation;
    2. the equations of the hyperbola and the asymptotes after the translation.

Question 5(a):
AnswerMarks Guidance
Working/AnswerMarks Guidance
Asymptotes are \(y = \pm\frac{1}{2}x\)M1A1 OE; M1 for \(y = \pm mx\)
Subtotal2
Question 5(b):
AnswerMarks Guidance
Working/AnswerMarks Guidance
\(x = 4\) substituted into equationM1
\(y^2 = 3\) so \(y = \pm\sqrt{3}\)A1 Allow NMS
Subtotal2
Question 5(c)(i):
AnswerMarks Guidance
Working/AnswerMarks Guidance
\(y\)-coords are \(2 \pm \sqrt{3}\)B1F ft wrong answer to (b)
Subtotal1
Question 5(c)(ii):
AnswerMarks Guidance
Working/AnswerMarks Guidance
Hyperbola is \(\frac{x^2}{4} - (y-2)^2 = 1\)M1A1 M1A0 if \(y+2\) used
Asymptotes are \(y = 2 \pm \frac{1}{2}x\)B1F ft wrong gradients in (a)
Subtotal3
Total8
## Question 5(a):

| Working/Answer | Marks | Guidance |
|---|---|---|
| Asymptotes are $y = \pm\frac{1}{2}x$ | M1A1 | OE; M1 for $y = \pm mx$ |
| **Subtotal** | **2** | |

## Question 5(b):

| Working/Answer | Marks | Guidance |
|---|---|---|
| $x = 4$ substituted into equation | M1 | |
| $y^2 = 3$ so $y = \pm\sqrt{3}$ | A1 | Allow NMS |
| **Subtotal** | **2** | |

## Question 5(c)(i):

| Working/Answer | Marks | Guidance |
|---|---|---|
| $y$-coords are $2 \pm \sqrt{3}$ | B1F | ft wrong answer to (b) |
| **Subtotal** | **1** | |

## Question 5(c)(ii):

| Working/Answer | Marks | Guidance |
|---|---|---|
| Hyperbola is $\frac{x^2}{4} - (y-2)^2 = 1$ | M1A1 | M1A0 if $y+2$ used |
| Asymptotes are $y = 2 \pm \frac{1}{2}x$ | B1F | ft wrong gradients in (a) |
| **Subtotal** | **3** | |
| **Total** | **8** | |

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5 The diagram shows the hyperbola

$$\frac { x ^ { 2 } } { 4 } - y ^ { 2 } = 1$$

and its asymptotes.\\
\includegraphics[max width=\textwidth, alt={}, center]{a0a30197-ca11-40d9-9ccd-30281c5e0fb4-03_531_1013_616_516}
\begin{enumerate}[label=(\alph*)]
\item Write down the equations of the two asymptotes.
\item The points on the hyperbola for which $x = 4$ are denoted by $A$ and $B$.

Find, in surd form, the $y$-coordinates of $A$ and $B$.
\item The hyperbola and its asymptotes are translated by two units in the positive $y$ direction.

Write down:
\begin{enumerate}[label=(\roman*)]
\item the $y$-coordinates of the image points of $A$ and $B$ under this translation;
\item the equations of the hyperbola and the asymptotes after the translation.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{AQA FP1 2008 Q5 [8]}}