Moderate -0.3 This is a straightforward volumes of revolution question requiring the standard formula V = π∫y² dx with a simple power function. The integration of (x-2)^5 is routine, and finding exact values at the limits involves basic arithmetic. Slightly easier than average due to the direct application of a standard technique with no complications.
2 The diagram shows the curve with equation \(y = \sqrt { ( x - 2 ) ^ { 5 } }\) for \(x \geqslant 2\).
\includegraphics[max width=\textwidth, alt={}, center]{59b896ae-60ce-49ea-9c70-0f76fc5fffae-2_885_1125_854_461}
The shaded region \(R\) is bounded by the curve \(y = \sqrt { ( x - 2 ) ^ { 5 } }\), the \(x\)-axis and the lines \(x = 3\) and \(x = 4\).
Find the exact value of the volume of the solid formed when the region \(R\) is rotated through \(360 ^ { \circ }\) about the \(x\)-axis.
2 The diagram shows the curve with equation $y = \sqrt { ( x - 2 ) ^ { 5 } }$ for $x \geqslant 2$.\\
\includegraphics[max width=\textwidth, alt={}, center]{59b896ae-60ce-49ea-9c70-0f76fc5fffae-2_885_1125_854_461}
The shaded region $R$ is bounded by the curve $y = \sqrt { ( x - 2 ) ^ { 5 } }$, the $x$-axis and the lines $x = 3$ and $x = 4$.
Find the exact value of the volume of the solid formed when the region $R$ is rotated through $360 ^ { \circ }$ about the $x$-axis.
\hfill \mbox{\textit{AQA C3 2009 Q2 [4]}}