Edexcel FP2 AS 2023 June — Question 3 7 marks

Exam BoardEdexcel
ModuleFP2 AS (Further Pure 2 AS)
Year2023
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComplex Numbers Argand & Loci
TypeCartesian equation from argument condition
DifficultyChallenging +1.2 This is a standard Further Maths locus problem requiring recognition that arg((z-a)/(z-b))=π/2 gives a semicircular arc, then finding the maximum distance from origin to points on this locus. While it requires geometric insight about argument loci and optimization, these are well-practiced FP2 techniques with straightforward execution once the setup is recognized.
Spec4.02k Argand diagrams: geometric interpretation4.02o Loci in Argand diagram: circles, half-lines

  1. A complex number \(z\) is represented by the point \(P\) on an Argand diagram.
Given that $$\arg \left( \frac { z - 4 - i } { z - 2 - 7 i } \right) = \frac { \pi } { 2 }$$
  1. sketch the locus of \(P\) as \(z\) varies,
  2. determine the exact maximum possible value of \(| z |\)

Question 3:
Part (a):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Draws part of a circle with end points \((4,1)\) and \((2,7)\)M1 1.1b
A semi-circle with end points \((4,1)\) and \((2,7)\) to the rightA1 1.1b
(2 marks)
Part (b):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Centre \((3, 4)\)B1 2.2a - Deduces the correct centre coordinates
\(r = \sqrt{(4-\text{"3"})^2 + (1-\text{"4"})^2}\) or \(r = \sqrt{(2-\text{"3"})^2 + (7-\text{"4"})^2}\) or \(r = \frac{1}{2}\sqrt{(4-2)^2 + (1-7)^2}\)M1 1.1b - Uses Pythagoras and their centre to find the radius
\(d = \sqrt{(\text{"3"}-0)^2 + (\text{"4"}-0)^2}\)M1 1.1b - Finds the distance from the origin to their centre using Pythagoras
Adds this distance to their radiusdM1 3.1a - Dependent on previous M mark; complete method to find maximum \(
\(z = 5 + \sqrt{10}\)
(5 marks)
## Question 3:

### Part (a):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Draws part of a circle with end points $(4,1)$ and $(2,7)$ | M1 | 1.1b |
| A semi-circle with end points $(4,1)$ and $(2,7)$ to the right | A1 | 1.1b |
| **(2 marks)** | | |

### Part (b):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Centre $(3, 4)$ | B1 | 2.2a - Deduces the correct centre coordinates |
| $r = \sqrt{(4-\text{"3"})^2 + (1-\text{"4"})^2}$ or $r = \sqrt{(2-\text{"3"})^2 + (7-\text{"4"})^2}$ or $r = \frac{1}{2}\sqrt{(4-2)^2 + (1-7)^2}$ | M1 | 1.1b - Uses Pythagoras and their centre to find the radius |
| $d = \sqrt{(\text{"3"}-0)^2 + (\text{"4"}-0)^2}$ | M1 | 1.1b - Finds the distance from the origin to their centre using Pythagoras |
| Adds this distance to their radius | dM1 | 3.1a - Dependent on previous M mark; complete method to find maximum $|z|$ |
| $|z| = 5 + \sqrt{10}$ | A1 | 1.1b |
| **(5 marks)** | | |

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\begin{enumerate}
  \item A complex number $z$ is represented by the point $P$ on an Argand diagram.
\end{enumerate}

Given that

$$\arg \left( \frac { z - 4 - i } { z - 2 - 7 i } \right) = \frac { \pi } { 2 }$$

(a) sketch the locus of $P$ as $z$ varies,\\
(b) determine the exact maximum possible value of $| z |$

\hfill \mbox{\textit{Edexcel FP2 AS 2023 Q3 [7]}}