OCR MEI Further Pure Core AS 2024 June — Question 7 6 marks

Exam BoardOCR MEI
ModuleFurther Pure Core AS (Further Pure Core AS)
Year2024
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
Topic3x3 Matrices
TypeGeometric interpretation of systems
DifficultyStandard +0.8 This question requires understanding of determinants to determine solution existence, geometric interpretation of singular systems (sheaf of planes through origin for k=0), and recognizing a prism configuration for k=1. It combines matrix theory with 3D geometry requiring conceptual understanding beyond routine calculation, placing it moderately above average difficulty.
Spec4.03j Determinant 3x3: calculation4.03s Consistent/inconsistent: systems of equations

7 Three planes have equations $$\begin{array} { r } x + 2 y - 3 z = 0 \\ - x + 3 y - 2 z = 0 \\ x - 2 y + k z = k \end{array}$$ where \(k\) is a constant.
  1. For the case \(k = 0\), the origin lies on all three planes. Use a determinant to explain whether there are any other points that lie on all three planes in this case.
  2. You are now given that \(k = 1\).
    1. Show that there are no points that lie on all three planes.
    2. Describe the geometrical arrangement of the three planes.

Question 7:
AnswerMarks Guidance
7(a) 1 2 − 3
− 1 3 − 2 = − 5
1 − 2 0
Non-zero value means there are no other points that lie
AnswerMarks
on all three planesB1
B1
AnswerMarks
[2]1.1
2.4det = −5
correct conclusion with reference to non-zero determinant
AnswerMarks Guidance
7(b) (i)
5y – 5z = 0, y – z = 1
AnswerMarks
Inconsistent equations, so planes have no common pointM1
A1
A1
AnswerMarks
[3]3.1a
1.1
AnswerMarks
2.2aCan eliminate any of x, y, z
oe
from correct working
AnswerMarks Guidance
7(b) (ii)
[1]1.2 accept ‘prism’, ‘triangular prism’. Accept a diagram
Question 7:
7 | (a) | 1 2 − 3
− 1 3 − 2 = − 5
1 − 2 0
Non-zero value means there are no other points that lie
on all three planes | B1
B1
[2] | 1.1
2.4 | det = −5
correct conclusion with reference to non-zero determinant
7 | (b) | (i) | Eliminate one variable, e.g. x
5y – 5z = 0, y – z = 1
Inconsistent equations, so planes have no common point | M1
A1
A1
[3] | 3.1a
1.1
2.2a | Can eliminate any of x, y, z
oe
from correct working
7 | (b) | (ii) | The planes form a prismatic intersection | B1
[1] | 1.2 | accept ‘prism’, ‘triangular prism’. Accept a diagram
7 Three planes have equations

$$\begin{array} { r } 
x + 2 y - 3 z = 0 \\
- x + 3 y - 2 z = 0 \\
x - 2 y + k z = k
\end{array}$$

where $k$ is a constant.
\begin{enumerate}[label=(\alph*)]
\item For the case $k = 0$, the origin lies on all three planes.

Use a determinant to explain whether there are any other points that lie on all three planes in this case.
\item You are now given that $k = 1$.
\begin{enumerate}[label=(\roman*)]
\item Show that there are no points that lie on all three planes.
\item Describe the geometrical arrangement of the three planes.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{OCR MEI Further Pure Core AS 2024 Q7 [6]}}