AQA FP2 2011 January — Question 4 11 marks

Exam BoardAQA
ModuleFP2 (Further Pure Mathematics 2)
Year2011
SessionJanuary
Marks11
PaperDownload PDF ↗
TopicHyperbolic functions
TypeFind stationary points of hyperbolic curves
DifficultyStandard +0.8 This is a Further Maths question requiring differentiation of hyperbolic functions, solving a transcendental equation (likely requiring logarithms), and algebraic manipulation to verify a relationship. While the techniques are standard for FP2, the multi-step nature and need to handle the transcendental equation elevate it above routine exercises.
Spec4.07a Hyperbolic definitions: sinh, cosh, tanh as exponentials4.07d Differentiate/integrate: hyperbolic functions

4
  1. Prove that the curve $$y = 12 \cosh x - 8 \sinh x - x$$ has exactly one stationary point.
  2. Given that the coordinates of this stationary point are \(( a , b )\), show that \(a + b = 9\).

4
\begin{enumerate}[label=(\alph*)]
\item Prove that the curve

$$y = 12 \cosh x - 8 \sinh x - x$$

has exactly one stationary point.
\item Given that the coordinates of this stationary point are $( a , b )$, show that $a + b = 9$.
\end{enumerate}

\hfill \mbox{\textit{AQA FP2 2011 Q4 [11]}}