CAIE P3 2022 June — Question 5 8 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2022
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFactor & Remainder Theorem
TypeMultiple unknowns with derivative condition
DifficultyStandard +0.3 This is a straightforward application of the factor theorem with a derivative condition. Students substitute x=2 into both p(x) and p'(x) to get two simultaneous equations in a and b, then solve. The factorisation in part (b) follows immediately. While it requires understanding that a factor of both p(x) and p'(x) means a repeated root, the algebraic manipulation is routine for A-level, making this slightly easier than average.
Spec1.02j Manipulate polynomials: expanding, factorising, division, factor theorem1.07i Differentiate x^n: for rational n and sums

5 The polynomial \(a x ^ { 3 } - 10 x ^ { 2 } + b x + 8\), where \(a\) and \(b\) are constants, is denoted by \(\mathrm { p } ( x )\). It is given that \(( x - 2 )\) is a factor of both \(\mathrm { p } ( x )\) and \(\mathrm { p } ^ { \prime } ( x )\).
  1. Find the values of \(a\) and \(b\).
  2. When \(a\) and \(b\) have these values, factorise \(\mathrm { p } ( x )\) completely.

Question 5(a):
AnswerMarks Guidance
AnswerMark Guidance
Substitute \(x=2\), equate to zeroM1 Or divide by \(x-2\) and equate constant remainder to zero
Obtain a correct equation e.g. \(8a-40+2b+8=0\)A1 Seen or implied in subsequent work
Differentiate \(p(x)\), substitute \(x=2\) and equate result to zeroM1 Or divide by \(x-2\) and equate constant remainder to zero
Obtain \(12a-40+b=0\), or equivalentA1 SOI in subsequent work
Obtain \(a=3\) and \(b=4\)A1
Alternative method:
AnswerMarks Guidance
AnswerMark Guidance
State or imply \((x-2)^2\) is a factorM1
\(p(x)=(x-2)^2(ax+2)\)A1
Obtain an equation in \(b\)M1
e.g. by comparing coefficients of \(x\): \(b=4a-8\)A1
Obtain \(a=3\) and \(b=4\)A1 SC: If uses \(x=-2\) in both equations allow M1 and allow A1 for \(a=-3\), \(b=-4\)
Total: 5 marks
Question 5(b):
AnswerMarks Guidance
AnswerMark Guidance
Attempt division by \((x-2)\)M1 M1 earned if division reaches partial quotient of \(ax^2+kx\), or if inspection has unknown factor \(ax^2+ex+f\) and equation in \(e\) and/or \(f\), where \(a\) has value found in part 5(a)
Obtain quadratic factor \(3x^2-4x-4\)A1
Obtain factorisation \((3x+2)(x-2)(x-2)\)A1
Alternative method:
AnswerMarks Guidance
AnswerMark Guidance
State or imply \((x-2)^2\) is a factorB1
Attempt division by \((x-2)^2\), reaching quotient \(ax+k\) or use inspection with unknown factor \(cx+d\) reaching value for \(c\) or \(d\)M1
Obtain factorisation \((3x+2)(x-2)^2\)A1 Accept \(3\left(x+\frac{2}{3}\right)(x-2)^2\)
Total: 3 marks
## Question 5(a):

| Answer | Mark | Guidance |
|--------|------|----------|
| Substitute $x=2$, equate to zero | M1 | Or divide by $x-2$ and equate constant remainder to zero |
| Obtain a correct equation e.g. $8a-40+2b+8=0$ | A1 | Seen or implied in subsequent work |
| Differentiate $p(x)$, substitute $x=2$ and equate result to zero | M1 | Or divide by $x-2$ and equate constant remainder to zero |
| Obtain $12a-40+b=0$, or equivalent | A1 | SOI in subsequent work |
| Obtain $a=3$ and $b=4$ | A1 | |

**Alternative method:**

| Answer | Mark | Guidance |
|--------|------|----------|
| State or imply $(x-2)^2$ is a factor | M1 | |
| $p(x)=(x-2)^2(ax+2)$ | A1 | |
| Obtain an equation in $b$ | M1 | |
| e.g. by comparing coefficients of $x$: $b=4a-8$ | A1 | |
| Obtain $a=3$ and $b=4$ | A1 | SC: If uses $x=-2$ in both equations allow **M1** and allow **A1** for $a=-3$, $b=-4$ |

**Total: 5 marks**

---

## Question 5(b):

| Answer | Mark | Guidance |
|--------|------|----------|
| Attempt division by $(x-2)$ | M1 | M1 earned if division reaches partial quotient of $ax^2+kx$, or if inspection has unknown factor $ax^2+ex+f$ and equation in $e$ and/or $f$, where $a$ has value found in part **5(a)** |
| Obtain quadratic factor $3x^2-4x-4$ | A1 | |
| Obtain factorisation $(3x+2)(x-2)(x-2)$ | A1 | |

**Alternative method:**

| Answer | Mark | Guidance |
|--------|------|----------|
| State or imply $(x-2)^2$ is a factor | B1 | |
| Attempt division by $(x-2)^2$, reaching quotient $ax+k$ or use inspection with unknown factor $cx+d$ reaching value for $c$ or $d$ | M1 | |
| Obtain factorisation $(3x+2)(x-2)^2$ | A1 | Accept $3\left(x+\frac{2}{3}\right)(x-2)^2$ |

**Total: 3 marks**
5 The polynomial $a x ^ { 3 } - 10 x ^ { 2 } + b x + 8$, where $a$ and $b$ are constants, is denoted by $\mathrm { p } ( x )$. It is given that $( x - 2 )$ is a factor of both $\mathrm { p } ( x )$ and $\mathrm { p } ^ { \prime } ( x )$.
\begin{enumerate}[label=(\alph*)]
\item Find the values of $a$ and $b$.
\item When $a$ and $b$ have these values, factorise $\mathrm { p } ( x )$ completely.
\end{enumerate}

\hfill \mbox{\textit{CAIE P3 2022 Q5 [8]}}