CAIE P3 2022 June — Question 9 9 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2022
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVectors: Lines & Planes
TypePerpendicular distance point to line
DifficultyStandard +0.3 This is a standard Further Maths vectors question involving a cuboid setup with routine calculations: finding position vectors using given ratios, writing a line equation, and computing perpendicular distance using the standard formula |OM × d|/|d|. While it requires multiple steps and careful coordinate work, all techniques are direct applications of standard methods with no novel insight required. Slightly easier than average due to the structured parts guiding the solution.
Spec1.10a Vectors in 2D: i,j notation and column vectors1.10b Vectors in 3D: i,j,k notation1.10d Vector operations: addition and scalar multiplication1.10e Position vectors: and displacement4.04a Line equations: 2D and 3D, cartesian and vector forms

9 \includegraphics[max width=\textwidth, alt={}, center]{c1fbc9ef-2dc6-43c3-bc58-179f683c9acf-16_696_1104_264_518} In the diagram, \(O A B C D E F G\) is a cuboid in which \(O A = 2\) units, \(O C = 4\) units and \(O G = 2\) units. Unit vectors \(\mathbf { i } , \mathbf { j }\) and \(\mathbf { k }\) are parallel to \(O A , O C\) and \(O G\) respectively. The point \(M\) is the midpoint of \(D F\). The point \(N\) on \(A B\) is such that \(A N = 3 N B\).
  1. Express the vectors \(\overrightarrow { O M }\) and \(\overrightarrow { M N }\) in terms of \(\mathbf { i } , \mathbf { j }\) and \(\mathbf { k }\).
  2. Find a vector equation for the line through \(M\) and \(N\).
  3. Show that the length of the perpendicular from \(O\) to the line through \(M\) and \(N\) is \(\sqrt { \frac { 53 } { 6 } }\).

Question 9:
Part 9(a):
AnswerMarks Guidance
AnswerMark Guidance
Obtain \(\overrightarrow{OM} = \mathbf{i} + 2\mathbf{j} + 2\mathbf{k}\)B1
Use a correct method to find \(\overrightarrow{MN}\)M1 e.g. \(\overrightarrow{MO}+\overrightarrow{OA}+\overrightarrow{AN}\) or \(\overrightarrow{MO}+\overrightarrow{ON}\)
Obtain \(\overrightarrow{MN} = \mathbf{i}+\mathbf{j}-2\mathbf{k}\)A1 Accept any notation
Part 9(b):
AnswerMarks Guidance
AnswerMark Guidance
Use a correct method to form an equation for \(MN\)M1 Allow without \(\mathbf{r} = \ldots\)
Obtain \(\mathbf{r} = 2\mathbf{i}+3\mathbf{j}+\lambda(\mathbf{i}+\mathbf{j}-2\mathbf{k})\)A1 FT OE e.g. \(\mathbf{r}=\mathbf{i}+2\mathbf{j}+2\mathbf{k}+\mu(\mathbf{i}+\mathbf{j}-2\mathbf{k})\). Must have \(\mathbf{r}=\ldots\) Follow their answers to part 9(a)
Part 9(c):
AnswerMarks Guidance
AnswerMark Guidance
State \(\overrightarrow{OP}\) for a general point \(P\) on \(MN\) in component form, e.g. \((2+\lambda, 3+\lambda, -2\lambda)\)B1
Equate scalar product of \(\overrightarrow{OP}\) and a direction vector for \(MN\) to zero and solve for \(\lambda\)M1
Obtain \(\lambda = -\frac{5}{6}\)A1 OE e.g. \(\mu = \frac{1}{6}\)
Obtain \(\sqrt{\frac{53}{6}}\) correctlyA1 AG e.g. from \(\sqrt{\left(\frac{7}{6}\right)^2+\left(\frac{13}{6}\right)^2+\left(\frac{5}{3}\right)^2}\)
## Question 9:

### Part 9(a):

| Answer | Mark | Guidance |
|--------|------|----------|
| Obtain $\overrightarrow{OM} = \mathbf{i} + 2\mathbf{j} + 2\mathbf{k}$ | B1 | |
| Use a correct method to find $\overrightarrow{MN}$ | M1 | e.g. $\overrightarrow{MO}+\overrightarrow{OA}+\overrightarrow{AN}$ or $\overrightarrow{MO}+\overrightarrow{ON}$ |
| Obtain $\overrightarrow{MN} = \mathbf{i}+\mathbf{j}-2\mathbf{k}$ | A1 | Accept any notation |

### Part 9(b):

| Answer | Mark | Guidance |
|--------|------|----------|
| Use a correct method to form an equation for $MN$ | M1 | Allow without $\mathbf{r} = \ldots$ |
| Obtain $\mathbf{r} = 2\mathbf{i}+3\mathbf{j}+\lambda(\mathbf{i}+\mathbf{j}-2\mathbf{k})$ | A1 FT | OE e.g. $\mathbf{r}=\mathbf{i}+2\mathbf{j}+2\mathbf{k}+\mu(\mathbf{i}+\mathbf{j}-2\mathbf{k})$. Must have $\mathbf{r}=\ldots$ Follow their answers to part 9(a) |

### Part 9(c):

| Answer | Mark | Guidance |
|--------|------|----------|
| State $\overrightarrow{OP}$ for a general point $P$ on $MN$ in component form, e.g. $(2+\lambda, 3+\lambda, -2\lambda)$ | B1 | |
| Equate scalar product of $\overrightarrow{OP}$ and a direction vector for $MN$ to zero and solve for $\lambda$ | M1 | |
| Obtain $\lambda = -\frac{5}{6}$ | A1 | OE e.g. $\mu = \frac{1}{6}$ |
| Obtain $\sqrt{\frac{53}{6}}$ correctly | A1 | AG e.g. from $\sqrt{\left(\frac{7}{6}\right)^2+\left(\frac{13}{6}\right)^2+\left(\frac{5}{3}\right)^2}$ |

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\includegraphics[max width=\textwidth, alt={}, center]{c1fbc9ef-2dc6-43c3-bc58-179f683c9acf-16_696_1104_264_518}

In the diagram, $O A B C D E F G$ is a cuboid in which $O A = 2$ units, $O C = 4$ units and $O G = 2$ units. Unit vectors $\mathbf { i } , \mathbf { j }$ and $\mathbf { k }$ are parallel to $O A , O C$ and $O G$ respectively. The point $M$ is the midpoint of $D F$. The point $N$ on $A B$ is such that $A N = 3 N B$.
\begin{enumerate}[label=(\alph*)]
\item Express the vectors $\overrightarrow { O M }$ and $\overrightarrow { M N }$ in terms of $\mathbf { i } , \mathbf { j }$ and $\mathbf { k }$.
\item Find a vector equation for the line through $M$ and $N$.
\item Show that the length of the perpendicular from $O$ to the line through $M$ and $N$ is $\sqrt { \frac { 53 } { 6 } }$.
\end{enumerate}

\hfill \mbox{\textit{CAIE P3 2022 Q9 [9]}}