AQA S2 2006 January — Question 3 9 marks

Exam BoardAQA
ModuleS2 (Statistics 2)
Year2006
SessionJanuary
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicT-tests (unknown variance)
TypeSingle sample confidence interval t-distribution
DifficultyStandard +0.3 This is a straightforward t-distribution confidence interval question with clear data and standard procedures. While it requires knowing the t-distribution formula and interpretation, it's a routine textbook exercise with no conceptual challenges—slightly easier than average since the calculations are simple with n=9 and the data is clean.
Spec5.05d Confidence intervals: using normal distribution

3 The time, \(T\) minutes, that parents have to wait before seeing a mathematics teacher at a school parents' evening can be modelled by a normal distribution with mean \(\mu\) and standard deviation \(\sigma\). At a recent parents' evening, a random sample of 9 parents was asked to record the times that they waited before seeing a mathematics teacher. The times, in minutes, are $$\begin{array} { l l l l l l l l l } 5 & 12 & 10 & 8 & 7 & 6 & 9 & 7 & 8 \end{array}$$
  1. Construct a \(90 \%\) confidence interval for \(\mu\).
  2. Comment on the headteacher's claim that the mean time that parents have to wait before seeing a mathematics teacher is 5 minutes.

3(a)
AnswerMarks Guidance
\(\bar{x} = 8.0\)B1
\(S = 2.121\)B1
\(\nu = 8\)B1
\(t = 1.860\)B1√
\(90\%\) confidence interval for \(\mu\):
AnswerMarks Guidance
\[= 8 \pm 1.860\left(\frac{2.121}{3}\right)\]M1
\[= 8 \pm 1.315\]A1ft
\[= (6.68, 9.32)\]A1 7 marks
3(b)
AnswerMarks Guidance
The Headteacher's claim seems to be slightly optimisticE1ft
because value of 5 outside the confidence intervalE1ft 2 marks
Question 3 Total: 9 marks
**3(a)**
$\bar{x} = 8.0$ | B1 | |

$S = 2.121$ | B1 | |

$\nu = 8$ | B1 | |

$t = 1.860$ | B1√ | | (on their ν)

$90\%$ confidence interval for $\mu$:
$$= 8 \pm 1.860\left(\frac{2.121}{3}\right)$$ | M1 | |

$$= 8 \pm 1.315$$ | A1ft | |

$$= (6.68, 9.32)$$ | A1 | 7 marks | (6.68 to 6.69, 9.31 to 9.32)

**3(b)**
The Headteacher's claim seems to be slightly optimistic | E1ft | | Headteacher's claim isn't supported by the evidence **and**

because value of 5 outside the confidence interval | E1ft | 2 marks | It appears that the mean time to see a mathematics teacher is greater than 5 minutes

**Question 3 Total: 9 marks**

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3 The time, $T$ minutes, that parents have to wait before seeing a mathematics teacher at a school parents' evening can be modelled by a normal distribution with mean $\mu$ and standard deviation $\sigma$.

At a recent parents' evening, a random sample of 9 parents was asked to record the times that they waited before seeing a mathematics teacher.

The times, in minutes, are

$$\begin{array} { l l l l l l l l l } 
5 & 12 & 10 & 8 & 7 & 6 & 9 & 7 & 8
\end{array}$$
\begin{enumerate}[label=(\alph*)]
\item Construct a $90 \%$ confidence interval for $\mu$.
\item Comment on the headteacher's claim that the mean time that parents have to wait before seeing a mathematics teacher is 5 minutes.
\end{enumerate}

\hfill \mbox{\textit{AQA S2 2006 Q3 [9]}}