CAIE P2 2012 November — Question 7 8 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2012
SessionNovember
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPolynomial Division & Manipulation
TypeFinding Constants from Remainder Conditions
DifficultyModerate -0.3 This is a straightforward application of the Remainder Theorem to find two unknowns from two conditions, followed by polynomial long division. Both parts require standard techniques with no novel insight—slightly easier than average due to the mechanical nature of the algebra involved.
Spec1.02j Manipulate polynomials: expanding, factorising, division, factor theorem1.02k Simplify rational expressions: factorising, cancelling, algebraic division

7 The polynomial \(2 x ^ { 3 } - 4 x ^ { 2 } + a x + b\), where \(a\) and \(b\) are constants, is denoted by \(\mathrm { p } ( x )\). It is given that when \(\mathrm { p } ( x )\) is divided by \(( x + 1 )\) the remainder is 4 , and that when \(\mathrm { p } ( x )\) is divided by \(( x - 3 )\) the remainder is 12 .
  1. Find the values of \(a\) and \(b\).
  2. When \(a\) and \(b\) have these values, find the quotient and remainder when \(\mathrm { p } ( x )\) is divided by ( \(x ^ { 2 } - 2\) ).

AnswerMarks Guidance
(i) Substitute \(x = -1\), equate to zero and obtain a correct equation in any formB1
Substitute \(x = 3\) and equate to 12M1
Obtain a correct equation in any formA1
Solve a relevant pair of equations for \(a\) or for \(b\)M1
Obtain \(a = -4\) and \(b = 6\)A1 [5]
(ii) Attempt division by \(x^2 - 2\) and reach a partial quotient of \(2x - k\)M1
Obtain quotient \(2x - 4\)A1
Obtain remainder –2A1 [3]
(i) Substitute $x = -1$, equate to zero and obtain a correct equation in any form | B1 |
Substitute $x = 3$ and equate to 12 | M1 |
Obtain a correct equation in any form | A1 |
Solve a relevant pair of equations for $a$ or for $b$ | M1 |
Obtain $a = -4$ and $b = 6$ | A1 | [5]

(ii) Attempt division by $x^2 - 2$ and reach a partial quotient of $2x - k$ | M1 |
Obtain quotient $2x - 4$ | A1 |
Obtain remainder –2 | A1 | [3]
7 The polynomial $2 x ^ { 3 } - 4 x ^ { 2 } + a x + b$, where $a$ and $b$ are constants, is denoted by $\mathrm { p } ( x )$. It is given that when $\mathrm { p } ( x )$ is divided by $( x + 1 )$ the remainder is 4 , and that when $\mathrm { p } ( x )$ is divided by $( x - 3 )$ the remainder is 12 .\\
(i) Find the values of $a$ and $b$.\\
(ii) When $a$ and $b$ have these values, find the quotient and remainder when $\mathrm { p } ( x )$ is divided by ( $x ^ { 2 } - 2$ ).

\hfill \mbox{\textit{CAIE P2 2012 Q7 [8]}}