4 The parametric equations of a curve are
$$x = \ln ( 1 - 2 t ) , \quad y = \frac { 2 } { t } , \quad \text { for } t < 0$$
- Show that \(\frac { \mathrm { d } y } { \mathrm {~d} x } = \frac { 1 - 2 t } { t ^ { 2 } }\).
- Find the exact coordinates of the only point on the curve at which the gradient is 3 .