Standard +0.3 This is a straightforward modulus inequality requiring consideration of critical points at x=2 and x=-5, then testing regions or squaring both sides. While it requires systematic case analysis, it's a standard textbook exercise with no conceptual surprises, making it slightly easier than average.
Either state or imply non-modular inequality \((x-2)^2 \geq (x+5)^2\), or corresponding equation or pair of linear equations
M1
Obtain critical value \(-\frac{3}{2}\)
A1
State correct answer \(x \leq -\frac{3}{2}\)
A1
[3]
Or state a correct linear equation for the critical value, e.g. \(x - 2 = -x - 5\), or corresponding correct linear inequality, e.g. \(x - 2 \geq -x - 5\)
M1
Obtain critical value \(-\frac{3}{2}\)
A1
State correct answer \(x \leq -\frac{3}{2}\)
A1
[3]
Either state or imply non-modular inequality $(x-2)^2 \geq (x+5)^2$, or corresponding equation or pair of linear equations | M1 |
Obtain critical value $-\frac{3}{2}$ | A1 |
State correct answer $x \leq -\frac{3}{2}$ | A1 | [3]
Or state a correct linear equation for the critical value, e.g. $x - 2 = -x - 5$, or corresponding correct linear inequality, e.g. $x - 2 \geq -x - 5$ | M1 |
Obtain critical value $-\frac{3}{2}$ | A1 |
State correct answer $x \leq -\frac{3}{2}$ | A1 | [3]