AQA C3 2008 June — Question 2 9 marks

Exam BoardAQA
ModuleC3 (Core Mathematics 3)
Year2008
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicReciprocal Trig & Identities
TypeSolve equation using Pythagorean identities
DifficultyModerate -0.3 This is a straightforward multi-part question on reciprocal trig functions and Pythagorean identities. Part (a) is basic recall (sec x = 1/cos x), part (b) is a guided algebraic manipulation using tan²x = sec²x - 1, and part (c) applies the quadratic formula to solve. The question requires standard techniques with clear scaffolding, making it slightly easier than average for C3 level.
Spec1.05h Reciprocal trig functions: sec, cosec, cot definitions and graphs1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=11.05o Trigonometric equations: solve in given intervals

2
  1. Solve the equation \(\sec x = 3\), giving the values of \(x\) in radians to two decimal places in the interval \(0 \leqslant x < 2 \pi\).
  2. Show that the equation \(\tan ^ { 2 } x = 2 \sec x + 2\) can be written as \(\sec ^ { 2 } x - 2 \sec x - 3 = 0\).
  3. Solve the equation \(\tan ^ { 2 } x = 2 \sec x + 2\), giving the values of \(x\) in radians to two decimal places in the interval \(0 \leqslant x < 2 \pi\).

2(a)
AnswerMarks Guidance
\(x = \cos^{-1}\frac{1}{3} = 1.23, 5.05\) (0.39π, 1.61π)M1, A1, A1 PI; AWRT (−1 for each error in range); SC 70.53, 289.47 B1
2(b)
AnswerMarks Guidance
\(\sec^2 x - 1 = 2\sec x + 2\); \(\sec^2 x - 2\sec x - 3 = 0\)M1, A1 Use of \(\sec^2 x = 1 + \tan^2 x\); AG; CSO
2(c)
AnswerMarks Guidance
\(\sec^2 x - 2\sec x - 3 = 0\); \((\sec x - 3)(\sec x + 1) = 0\); \(\cos x = \frac{1}{3}\) or \(-1\); \(x = 1.23, 5.05, 3.14\) (π)M1, A1, B1f, B1 Attempt to solve; AG; CSO; (2 answers in range from (a)) AWRT all correct and no extras in range; SC 70.53, 289.47, 180 B1
Total: 9 marks
**2(a)**

| $x = \cos^{-1}\frac{1}{3} = 1.23, 5.05$ (0.39π, 1.61π) | M1, A1, A1 | PI; AWRT (−1 for each error in range); SC 70.53, 289.47 B1 |

**2(b)**

| $\sec^2 x - 1 = 2\sec x + 2$; $\sec^2 x - 2\sec x - 3 = 0$ | M1, A1 | Use of $\sec^2 x = 1 + \tan^2 x$; AG; CSO |

**2(c)**

| $\sec^2 x - 2\sec x - 3 = 0$; $(\sec x - 3)(\sec x + 1) = 0$; $\cos x = \frac{1}{3}$ or $-1$; $x = 1.23, 5.05, 3.14$ (π) | M1, A1, B1f, B1 | Attempt to solve; AG; CSO; (2 answers in range from (a)) AWRT all correct and no extras in range; SC 70.53, 289.47, 180 B1 |

**Total: 9 marks**

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2
\begin{enumerate}[label=(\alph*)]
\item Solve the equation $\sec x = 3$, giving the values of $x$ in radians to two decimal places in the interval $0 \leqslant x < 2 \pi$.
\item Show that the equation $\tan ^ { 2 } x = 2 \sec x + 2$ can be written as $\sec ^ { 2 } x - 2 \sec x - 3 = 0$.
\item Solve the equation $\tan ^ { 2 } x = 2 \sec x + 2$, giving the values of $x$ in radians to two decimal places in the interval $0 \leqslant x < 2 \pi$.
\end{enumerate}

\hfill \mbox{\textit{AQA C3 2008 Q2 [9]}}