AQA C3 2006 June — Question 4 8 marks

Exam BoardAQA
ModuleC3 (Core Mathematics 3)
Year2006
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicModulus function
TypeSketch two |linear| functions and solve related equation/inequality
DifficultyModerate -0.8 This is a straightforward modulus question requiring standard techniques: sketching basic modulus graphs (V-shapes with known vertices), solving by considering cases (x ≥ 0 and x < 0, plus 2x - 4 ≥ 0 and 2x - 4 < 0), and reading the inequality solution from the graph or algebraic work. All steps are routine textbook exercises with no novel insight required, making it easier than average.
Spec1.02l Modulus function: notation, relations, equations and inequalities1.02s Modulus graphs: sketch graph of |ax+b|1.02t Solve modulus equations: graphically with modulus function

4
  1. Sketch and label on the same set of axes the graphs of:
    1. \(y = | x |\);
    2. \(y = | 2 x - 4 |\).
    1. Solve the equation \(| x | = | 2 x - 4 |\).
    2. Hence, or otherwise, solve the inequality \(| x | > | 2 x - 4 |\).

4(a)(i)
AnswerMarks Guidance
Graph shownB1 \(y =
4(a)(ii)
AnswerMarks
M1 A12 branches mod graph \(x > 0\) for \(y = 0\); for 2, 4; 2 marks total
4(b)(i)
AnswerMarks Guidance
\(x = 2x - 4\), \(x = 4\); \(-x = 2x - 4\); \(x = \frac{4}{3}\)B1 M1 A1 OE one value only; 3 marks total
Alternative: \(x^2 = (2x-4)^2\); \(x = 4, \frac{4}{3}\)M1 A1 A1
4(b)(ii)
AnswerMarks
M1 A14 marks total
4(b)(iii)
AnswerMarks Guidance
\(\frac{4}{3} < x < 4\)M1 A1 \(\frac{4}{3}, 4\) (ft) identified as extremes; CAO; 2 marks total
Total for Question 4: 8 marks
### 4(a)(i)
Graph shown | B1 | $y = |x|$; 1 mark

### 4(a)(ii)
| M1 A1 | 2 branches mod graph $x > 0$ for $y = 0$; for 2, 4; 2 marks total

### 4(b)(i)
$x = 2x - 4$, $x = 4$; $-x = 2x - 4$; $x = \frac{4}{3}$ | B1 M1 A1 | OE one value only; 3 marks total

**Alternative:** $x^2 = (2x-4)^2$; $x = 4, \frac{4}{3}$ | M1 A1 A1 |

### 4(b)(ii)
| M1 A1 | 4 marks total

### 4(b)(iii)
$\frac{4}{3} < x < 4$ | M1 A1 | $\frac{4}{3}, 4$ (ft) identified as extremes; CAO; 2 marks total

**Total for Question 4:** 8 marks
4
\begin{enumerate}[label=(\alph*)]
\item Sketch and label on the same set of axes the graphs of:
\begin{enumerate}[label=(\roman*)]
\item $y = | x |$;
\item $y = | 2 x - 4 |$.
\end{enumerate}\item \begin{enumerate}[label=(\roman*)]
\item Solve the equation $| x | = | 2 x - 4 |$.
\item Hence, or otherwise, solve the inequality $| x | > | 2 x - 4 |$.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{AQA C3 2006 Q4 [8]}}