AQA C3 2006 June — Question 1 6 marks

Exam BoardAQA
ModuleC3 (Core Mathematics 3)
Year2006
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFixed Point Iteration
TypeRearrange to iterative form
DifficultyModerate -0.8 This is a straightforward textbook exercise on fixed-point iteration requiring only routine application of a given formula. Part (a) involves simple substitution to verify a sign change, part (b) is trivial algebraic rearrangement, and part (c) is mechanical calculator work with no problem-solving required. Significantly easier than average A-level questions.
Spec1.09a Sign change methods: locate roots1.09c Simple iterative methods: x_{n+1} = g(x_n), cobweb and staircase diagrams

1 The curve \(y = x ^ { 3 } - x - 7\) intersects the \(x\)-axis at the point where \(x = \alpha\).
  1. Show that \(\alpha\) lies between 2.0 and 2.1.
  2. Show that the equation \(x ^ { 3 } - x - 7 = 0\) can be rearranged in the form \(x = \sqrt [ 3 ] { x + 7 }\).
  3. Use the iteration \(x _ { n + 1 } = \sqrt [ 3 ] { x _ { n } + 7 }\) with \(x _ { 1 } = 2\) to find the values of \(x _ { 2 } , x _ { 3 }\) and \(x _ { 4 }\), giving your answers to three significant figures.

1(a)
AnswerMarks Guidance
\(f(2) = -1\) and \(f(2.1) = +0.161\) with change of sign: \(-2 < \alpha < 2.1\)M1 A1 both attempted; 2 marks total
1(b)
AnswerMarks Guidance
\(x^3 - x - 7 = 0 \Rightarrow x^3 = x + 7 \Rightarrow x = \sqrt[3]{x+7}\)B1 AG; 1 mark total
1(c)
AnswerMarks Guidance
\(x_1 = 2\); \(x_2 = 2.0801...\); \(x_3 = 2.0862...\); \(x_4 = 2.09\)M1 A1 A1 AWRT 2.08 and AWRT 2.09; 3 marks total
### 1(a)
$f(2) = -1$ and $f(2.1) = +0.161$ with change of sign: $-2 < \alpha < 2.1$ | M1 A1 | both attempted; 2 marks total

### 1(b)
$x^3 - x - 7 = 0 \Rightarrow x^3 = x + 7 \Rightarrow x = \sqrt[3]{x+7}$ | B1 | AG; 1 mark total

### 1(c)
$x_1 = 2$; $x_2 = 2.0801...$; $x_3 = 2.0862...$; $x_4 = 2.09$ | M1 A1 A1 | AWRT 2.08 and AWRT 2.09; 3 marks total
1 The curve $y = x ^ { 3 } - x - 7$ intersects the $x$-axis at the point where $x = \alpha$.
\begin{enumerate}[label=(\alph*)]
\item Show that $\alpha$ lies between 2.0 and 2.1.
\item Show that the equation $x ^ { 3 } - x - 7 = 0$ can be rearranged in the form $x = \sqrt [ 3 ] { x + 7 }$.
\item Use the iteration $x _ { n + 1 } = \sqrt [ 3 ] { x _ { n } + 7 }$ with $x _ { 1 } = 2$ to find the values of $x _ { 2 } , x _ { 3 }$ and $x _ { 4 }$, giving your answers to three significant figures.
\end{enumerate}

\hfill \mbox{\textit{AQA C3 2006 Q1 [6]}}