AQA C2 2008 June — Question 5 5 marks

Exam BoardAQA
ModuleC2 (Core Mathematics 2)
Year2008
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicLaws of Logarithms
TypeEvaluate log expression using laws
DifficultyEasy -1.2 This question tests basic logarithm laws through direct recall and simple application. Part (a) requires memorizing two fundamental log properties (log_a(1)=0 and log_a(a)=1), while part (b) involves straightforward application of addition/subtraction rules to find x=20. No problem-solving or insight needed—purely mechanical application of standard rules.
Spec1.06f Laws of logarithms: addition, subtraction, power rules

5
  1. Write down the value of:
    1. \(\log _ { a } 1\);
    2. \(\log _ { a } a\).
  2. Given that $$\log _ { a } x = \log _ { a } 5 + \log _ { a } 6 - \log _ { a } 1.5$$ find the value of \(x\).

AnswerMarks Guidance
(a)(i) \(\log_a 1 = 0\)B1 (1 mark)
(ii) \(\log_a a = 1\)B1 (1 mark)
(b) \(\log_a x = \log_a(5 \times 6) - \log_a 1.5\)M1 One law of logs used correctly
\(\log_a x = \log_a\left(\frac{5 \times 6}{1.5}\right)\)M1 A second law of logs used correctly
\(\log_a x = \log_a 20 \Rightarrow x = 20\)A1 (3 marks)
Total for Q5: 5 marks
**(a)(i)** $\log_a 1 = 0$ | B1 (1 mark)

**(ii)** $\log_a a = 1$ | B1 (1 mark)

**(b)** $\log_a x = \log_a(5 \times 6) - \log_a 1.5$ | M1 | One law of logs used correctly

$\log_a x = \log_a\left(\frac{5 \times 6}{1.5}\right)$ | M1 | A second law of logs used correctly

$\log_a x = \log_a 20 \Rightarrow x = 20$ | A1 (3 marks)

**Total for Q5: 5 marks**

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5
\begin{enumerate}[label=(\alph*)]
\item Write down the value of:
\begin{enumerate}[label=(\roman*)]
\item $\log _ { a } 1$;
\item $\log _ { a } a$.
\end{enumerate}\item Given that

$$\log _ { a } x = \log _ { a } 5 + \log _ { a } 6 - \log _ { a } 1.5$$

find the value of $x$.
\end{enumerate}

\hfill \mbox{\textit{AQA C2 2008 Q5 [5]}}