AQA C2 2008 June — Question 1 9 marks

Exam BoardAQA
ModuleC2 (Core Mathematics 2)
Year2008
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIndices and Surds
TypeDifferentiate after index conversion
DifficultyModerate -0.8 This is a straightforward C2 question testing basic index law recall (converting a surd to fractional power) and routine differentiation using the power rule. Part (a) is trivial recall, parts (b)(i) and (b)(ii) are standard textbook exercises requiring no problem-solving insight—just mechanical application of learned techniques.
Spec1.02a Indices: laws of indices for rational exponents1.07i Differentiate x^n: for rational n and sums1.07m Tangents and normals: gradient and equations

1
  1. Write \(\sqrt { x ^ { 3 } }\) in the form \(x ^ { k }\), where \(k\) is a fraction.
    (1 mark)
  2. A curve, defined for \(x \geqslant 0\), has equation $$y = x ^ { 2 } - \sqrt { x ^ { 3 } }$$
    1. Find \(\frac { \mathrm { d } y } { \mathrm {~d} x }\).
    2. Find the equation of the tangent to the curve at the point where \(x = 4\), giving your answer in the form \(y = m x + c\).

AnswerMarks Guidance
(a) \(\sqrt{x^3} = x^{\frac{3}{2}}\)B1 (1 mark) OE; accept '\(k = 1.5\)'
(b)(i) \(\frac{dy}{dx} = 2x - \frac{3}{2}x^{-\frac{1}{2}}\)M1, B1, A1F (3 marks) At least one index reduced by 1 and no term of the form \(\sqrt{ax^2}\); For \(2x\); For \(-1.5x^{0.5}\) Ft on ans (a) non-integer \(k\)
(b)(ii) When \(x = 4\), \(y = 8\)B1, M1, A1F (3 marks) Attempt to find \(\frac{dy}{dx}\) when \(x = 4\); Ft on one earlier error provided non-integer powers in (a) and (b)(i)
Tangent: \(y - 8 = 5(x - 4)\); \(y = 5x - 12\)m1, A1 \(y - y(4) = y'(4)[x - 4]\) OE; CSO; must be \(y = 5x - 12\)
Total for Q1: 9 marks
**(a)** $\sqrt{x^3} = x^{\frac{3}{2}}$ | B1 (1 mark) | OE; accept '$k = 1.5$'

**(b)(i)** $\frac{dy}{dx} = 2x - \frac{3}{2}x^{-\frac{1}{2}}$ | M1, B1, A1F (3 marks) | At least one index reduced by 1 and no term of the form $\sqrt{ax^2}$; For $2x$; For $-1.5x^{0.5}$ Ft on ans (a) non-integer $k$

**(b)(ii)** When $x = 4$, $y = 8$ | B1, M1, A1F (3 marks) | Attempt to find $\frac{dy}{dx}$ when $x = 4$; Ft on one earlier error provided non-integer powers in (a) and (b)(i)

Tangent: $y - 8 = 5(x - 4)$; $y = 5x - 12$ | m1, A1 | $y - y(4) = y'(4)[x - 4]$ OE; CSO; must be $y = 5x - 12$

**Total for Q1: 9 marks**

---
1
\begin{enumerate}[label=(\alph*)]
\item Write $\sqrt { x ^ { 3 } }$ in the form $x ^ { k }$, where $k$ is a fraction.\\
(1 mark)
\item A curve, defined for $x \geqslant 0$, has equation

$$y = x ^ { 2 } - \sqrt { x ^ { 3 } }$$
\begin{enumerate}[label=(\roman*)]
\item Find $\frac { \mathrm { d } y } { \mathrm {~d} x }$.
\item Find the equation of the tangent to the curve at the point where $x = 4$, giving your answer in the form $y = m x + c$.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{AQA C2 2008 Q1 [9]}}