AQA C2 2008 June — Question 2 6 marks

Exam BoardAQA
ModuleC2 (Core Mathematics 2)
Year2008
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicRadians, Arc Length and Sector Area
TypeSegment area calculation
DifficultyStandard +0.3 This is a straightforward C2 segment problem requiring standard formulas: arc length = rθ, isosceles triangle angle sum, and perimeter calculation. All steps are routine applications of basic radian geometry with no problem-solving insight needed, making it slightly easier than average.
Spec1.05b Sine and cosine rules: including ambiguous case1.05d Radians: arc length s=r*theta and sector area A=1/2 r^2 theta

2 The diagram shows a shaded segment of a circle with centre \(O\) and radius 14 cm , where \(P Q\) is a chord of the circle. \includegraphics[max width=\textwidth, alt={}, center]{a2525df8-dbd0-4b69-b6bb-f8ef6f96f7dc-2_423_551_1270_740} In triangle \(O P Q\), angle \(P O Q = \frac { 3 \pi } { 7 }\) radians and angle \(O P Q = \alpha\) radians.
  1. Find the length of the arc \(P Q\), giving your answer as a multiple of \(\pi\).
  2. Find \(\alpha\) in terms of \(\pi\).
  3. Find the perimeter of the shaded segment, giving your answer to three significant figures.

AnswerMarks Guidance
(a) Arc \(PQ = r\theta = 6\pi\) (cm)M1, A1 (2 marks) \(r\theta\); Condone missing units throughout the paper
(b) \(\alpha + \alpha + \frac{3\pi}{7} = \pi\); \(\alpha = \frac{2\pi}{7}\)M1, A1 (2 marks) OE; Accept equivalent fractions eg \(\frac{4\pi}{14}\) and condone \(0.286\pi\) or better
(c) Chord \(PQ = 2 \times 14 \times \cos\alpha\)M1 OE eg \(2 \times 14 \times \sin\frac{3\pi}{14}\) or \(17.45-17.5\) inclusive or \(\sqrt{14^2 + 14^2 - 2 \times 14^2 \times \cos\frac{3\pi}{7}}\)
Perimeter \(= 17.45\ldots + 6\pi = 36.307\ldots = 36.3\) (cm)A1 (2 marks) Condone > 3sf
Total for Q2: 6 marks
**(a)** Arc $PQ = r\theta = 6\pi$ (cm) | M1, A1 (2 marks) | $r\theta$; Condone missing units throughout the paper

**(b)** $\alpha + \alpha + \frac{3\pi}{7} = \pi$; $\alpha = \frac{2\pi}{7}$ | M1, A1 (2 marks) | OE; Accept equivalent fractions eg $\frac{4\pi}{14}$ and condone $0.286\pi$ or better

**(c)** Chord $PQ = 2 \times 14 \times \cos\alpha$ | M1 | OE eg $2 \times 14 \times \sin\frac{3\pi}{14}$ or $17.45-17.5$ inclusive or $\sqrt{14^2 + 14^2 - 2 \times 14^2 \times \cos\frac{3\pi}{7}}$

Perimeter $= 17.45\ldots + 6\pi = 36.307\ldots = 36.3$ (cm) | A1 (2 marks) | Condone > 3sf

**Total for Q2: 6 marks**

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2 The diagram shows a shaded segment of a circle with centre $O$ and radius 14 cm , where $P Q$ is a chord of the circle.\\
\includegraphics[max width=\textwidth, alt={}, center]{a2525df8-dbd0-4b69-b6bb-f8ef6f96f7dc-2_423_551_1270_740}

In triangle $O P Q$, angle $P O Q = \frac { 3 \pi } { 7 }$ radians and angle $O P Q = \alpha$ radians.
\begin{enumerate}[label=(\alph*)]
\item Find the length of the arc $P Q$, giving your answer as a multiple of $\pi$.
\item Find $\alpha$ in terms of $\pi$.
\item Find the perimeter of the shaded segment, giving your answer to three significant figures.
\end{enumerate}

\hfill \mbox{\textit{AQA C2 2008 Q2 [6]}}