AQA C1 2009 January — Question 2 4 marks

Exam BoardAQA
ModuleC1 (Core Mathematics 1)
Year2009
SessionJanuary
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSolving quadratics and applications
TypeQuadratic inequality solving
DifficultyModerate -0.8 This is a straightforward two-part question requiring factorisation of a quadratic (routine technique) followed by solving a quadratic inequality using the factored form. Both are standard C1 skills with no problem-solving insight required, making it easier than average but not trivial since students must correctly identify the solution interval from the inequality.
Spec1.02g Inequalities: linear and quadratic in single variable1.02j Manipulate polynomials: expanding, factorising, division, factor theorem

2
  1. Factorise \(2 x ^ { 2 } - 5 x + 3\).
  2. Hence, or otherwise, solve the inequality \(2 x ^ { 2 } - 5 x + 3 < 0\).

AnswerMarks Guidance
2(a)\((x-1)(2x-3)\) B1
2(b)Critical values are \(1, 1\frac{1}{2}\) B1
Sign diagram or sketchM1
\(\Rightarrow 1 < x < 1\frac{1}{2}\)A1 Full marks for correct inequality without working
Total: 4 marks
**2(a)** | $(x-1)(2x-3)$ | B1 | (1 - x)(3 - 2x) or $2(x-1)(x-1.5)$ etc

**2(b)** | Critical values are $1, 1\frac{1}{2}$ | B1 | Correct or ft their factors from (a)
| Sign diagram or sketch | M1 |
| $\Rightarrow 1 < x < 1\frac{1}{2}$ | A1 | Full marks for correct inequality without working

**Total: 4 marks**

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2
\begin{enumerate}[label=(\alph*)]
\item Factorise $2 x ^ { 2 } - 5 x + 3$.
\item Hence, or otherwise, solve the inequality $2 x ^ { 2 } - 5 x + 3 < 0$.
\end{enumerate}

\hfill \mbox{\textit{AQA C1 2009 Q2 [4]}}