Edexcel S3 2014 June — Question 2 7 marks

Exam BoardEdexcel
ModuleS3 (Statistics 3)
Year2014
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicChi-squared test of independence
TypeExpected frequencies partially provided
DifficultyStandard +0.3 This is a standard chi-squared test of independence with all calculations scaffolded: part (a) verifies given expected frequencies and contributions using routine formulas, while part (b) requires comparing a given test statistic to critical values. The question requires only procedural application of learned techniques with no problem-solving or conceptual insight, making it slightly easier than average.
Spec5.06a Chi-squared: contingency tables

  1. A survey asked a random sample of 200 people their age and the main use of their mobile phone.
The results are shown in Table 1 below. \begin{table}[h]
\multirow{2}{*}{}Main use of their mobile phone
InternetTextsPhone calls
\multirow{3}{*}{Age}Under 2027149
From 20 to 40323429
Over 40151921
\captionsetup{labelformat=empty} \caption{Table 1}
\end{table} The data are to be used to test whether or not age and main use of their mobile phone are independent. Table 2 shows the expected frequencies for each group, assuming people's age and main use of their mobile phone are independent. \begin{table}[h]
\multirow{2}{*}{}Main use of their mobile phone
InternetTextsPhone calls
\multirow{3}{*}{Age}Under 2018.516.7514.75
From 20 to 4035.1531.82528.025
Over 4020.3518.42516.225
\captionsetup{labelformat=empty} \caption{Table 2}
\end{table}
  1. For users under 20 choosing the Internet as the main use of their mobile phone,
    1. verify that the expected frequency is 18.5
    2. show that the contribution to the \(\chi ^ { 2 }\) test statistic is 3.91 to 3 significant figures.
  2. Given that the \(\chi ^ { 2 }\) test statistic for the data is 9.893 to 3 decimal places, test at the \(5 \%\) level of significance whether or not age and main use of their mobile phone are independent. State your hypotheses clearly.

2(a)(i)
AnswerMarks Guidance
AnswerMarks Guidance
Expected value \(= \frac{50 \times 74}{200} = 18.5\)B1 cso
\(\chi^2\) contribution \(= \frac{(27-18.5)^2}{18.5} = 3.905405405 = 3.91\) to 3sfB1 cso (2)
2(a)(ii)
AnswerMarks Guidance
AnswerMarks Guidance
2(b)
AnswerMarks Guidance
AnswerMarks Guidance
\(H_0\): users age and main mobile phone use are independent/no association between users age and main mobile phone use; \(H_1\): users age and main mobile phone use are not independent/ some association between users age and main mobile phone useB1
\(\nu = 4\)B1
Critical value \(\chi^2 = 9.488\)B1ft
Test statistic is in critical region therefore significant evidence to reject \(H_0\) and accept \(H_1\). Evidence at 5% level that age and main phone use are not independent.M1, A1ft (5) (7 marks)
Guidance Notes:
- 3rd B1 ft on their value of \(\nu\)
- M1 for attempt to compare test statistic and their critical value
- A1 ft on test statistic and critical value but must be comment in context. (A0 if hypotheses are the wrong way around)
**2(a)(i)**

| Answer | Marks | Guidance |
|--------|-------|----------|
| Expected value $= \frac{50 \times 74}{200} = 18.5$ | B1 cso | |
| $\chi^2$ contribution $= \frac{(27-18.5)^2}{18.5} = 3.905405405 = 3.91$ to 3sf | B1 cso | (2) |

**2(a)(ii)**

| Answer | Marks | Guidance |
|--------|-------|----------|
| | | |

**2(b)**

| Answer | Marks | Guidance |
|--------|-------|----------|
| $H_0$: users age and main mobile phone use are independent/no association between users age and main mobile phone use; $H_1$: users age and main mobile phone use are not independent/ some association between users age and main mobile phone use | B1 | |
| $\nu = 4$ | B1 | |
| Critical value $\chi^2 = 9.488$ | B1ft | |
| Test statistic is in critical region therefore significant evidence to reject $H_0$ and accept $H_1$. Evidence at 5% level that age and main phone use are not independent. | M1, A1ft | (5) (7 marks) |

**Guidance Notes:**
- 3rd B1 ft on their value of $\nu$
- M1 for attempt to compare test statistic and their critical value
- A1 ft on test statistic and critical value but must be comment in context. (A0 if hypotheses are the wrong way around)

---
\begin{enumerate}
  \item A survey asked a random sample of 200 people their age and the main use of their mobile phone.
\end{enumerate}

The results are shown in Table 1 below.

\begin{table}[h]
\begin{center}
\begin{tabular}{|l|l|l|l|l|}
\hline
\multicolumn{2}{|c|}{\multirow{2}{*}{}} & \multicolumn{3}{|c|}{Main use of their mobile phone} \\
\hline
 &  & Internet & Texts & Phone calls \\
\hline
\multirow{3}{*}{Age} & Under 20 & 27 & 14 & 9 \\
\hline
 & From 20 to 40 & 32 & 34 & 29 \\
\hline
 & Over 40 & 15 & 19 & 21 \\
\hline
\end{tabular}
\captionsetup{labelformat=empty}
\caption{Table 1}
\end{center}
\end{table}

The data are to be used to test whether or not age and main use of their mobile phone are independent.

Table 2 shows the expected frequencies for each group, assuming people's age and main use of their mobile phone are independent.

\begin{table}[h]
\begin{center}
\begin{tabular}{|l|l|l|l|l|}
\hline
\multicolumn{2}{|c|}{\multirow{2}{*}{}} & \multicolumn{3}{|c|}{Main use of their mobile phone} \\
\hline
 &  & Internet & Texts & Phone calls \\
\hline
\multirow{3}{*}{Age} & Under 20 & 18.5 & 16.75 & 14.75 \\
\hline
 & From 20 to 40 & 35.15 & 31.825 & 28.025 \\
\hline
 & Over 40 & 20.35 & 18.425 & 16.225 \\
\hline
\end{tabular}
\captionsetup{labelformat=empty}
\caption{Table 2}
\end{center}
\end{table}

(a) For users under 20 choosing the Internet as the main use of their mobile phone,\\
(i) verify that the expected frequency is 18.5\\
(ii) show that the contribution to the $\chi ^ { 2 }$ test statistic is 3.91 to 3 significant figures.\\
(b) Given that the $\chi ^ { 2 }$ test statistic for the data is 9.893 to 3 decimal places, test at the $5 \%$ level of significance whether or not age and main use of their mobile phone are independent. State your hypotheses clearly.\\

\hfill \mbox{\textit{Edexcel S3 2014 Q2 [7]}}