Edexcel S3 2014 June — Question 4 6 marks

Exam BoardEdexcel
ModuleS3 (Statistics 3)
Year2014
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicType I/II errors and power of test
TypeFind sample size from partial test information
DifficultyChallenging +1.2 This question requires understanding of hypothesis testing mechanics (finding critical values, test statistics) and working backwards from a rejection decision. While it involves multiple steps (finding critical region, setting up inequality with unknown value, solving), the concepts are standard S3 material with straightforward algebraic manipulation. The 'reverse engineering' aspect adds modest problem-solving demand beyond routine textbook exercises.
Spec2.05e Hypothesis test for normal mean: known variance

4. A manufacturing company produces solar panels. The output of each solar panel is normally distributed with standard deviation 6 watts. It is thought that the mean output, \(\mu\), is 160 watts. A researcher believes that the mean output of the solar panels is greater than 160 watts. He writes down the output values of 5 randomly selected solar panels. He uses the data to carry out a hypothesis test at the \(5 \%\) level of significance. He tests \(\mathrm { H } _ { 0 } : \mu = 160\) against \(\mathrm { H } _ { 1 } : \mu > 160\) On reporting to his manager, the researcher can only find 4 of the output values. These are shown below $$\begin{array} { l l l l } 168.2 & 157.4 & 173.3 & 161.1 \end{array}$$ Given that the result of the hypothesis test is that there is significant evidence to reject \(\mathrm { H } _ { 0 }\) at the \(5 \%\) level of significance, calculate the minimum possible missing output value, \(\alpha\). Give your answer correct to 1 decimal place.

4
AnswerMarks Guidance
AnswerMarks Guidance
Test statistic, \(z = \frac{132 + \frac{\alpha}{5} - 160}{\frac{6}{\sqrt{5}}}\)M1A1ft
Critical \(z\) values is 1.6449B1
Therefore the test statistic is significant if \(\frac{132 + \frac{\alpha}{5} - 160}{\frac{6}{\sqrt{5}}} > 1.6449\)M1
Therefore \(132 + \frac{\alpha}{5} - 160 > 1.6449 \times \frac{6}{\sqrt{5}}\)
\(\alpha > 5\left(1.6449 \times \frac{6}{\sqrt{5}} + 28\right)\)
\(\alpha > 162.0686493...\)A1
Accept awrt 162.1 (6) (6 marks)
Guidance Notes:
- 1st A1 ft on their \(\bar{x}\)
- 1st B1 given for 1.6449 seen (condone sign)
- 3rd M1 inequality using their test statistic, accept incorrect signs for M1
**4**

| Answer | Marks | Guidance |
|--------|-------|----------|
| Test statistic, $z = \frac{132 + \frac{\alpha}{5} - 160}{\frac{6}{\sqrt{5}}}$ | M1A1ft | |
| Critical $z$ values is 1.6449 | B1 | |
| Therefore the test statistic is significant if $\frac{132 + \frac{\alpha}{5} - 160}{\frac{6}{\sqrt{5}}} > 1.6449$ | M1 | |
| Therefore $132 + \frac{\alpha}{5} - 160 > 1.6449 \times \frac{6}{\sqrt{5}}$ | | |
| $\alpha > 5\left(1.6449 \times \frac{6}{\sqrt{5}} + 28\right)$ | | |
| $\alpha > 162.0686493...$ | A1 | |
| Accept awrt 162.1 | | (6) (6 marks) |

**Guidance Notes:**
- 1st A1 ft on their $\bar{x}$
- 1st B1 given for 1.6449 seen (condone sign)
- 3rd M1 inequality using their test statistic, accept incorrect signs for M1

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4. A manufacturing company produces solar panels. The output of each solar panel is normally distributed with standard deviation 6 watts. It is thought that the mean output, $\mu$, is 160 watts.

A researcher believes that the mean output of the solar panels is greater than 160 watts. He writes down the output values of 5 randomly selected solar panels. He uses the data to carry out a hypothesis test at the $5 \%$ level of significance.

He tests $\mathrm { H } _ { 0 } : \mu = 160$ against $\mathrm { H } _ { 1 } : \mu > 160$\\
On reporting to his manager, the researcher can only find 4 of the output values. These are shown below

$$\begin{array} { l l l l } 
168.2 & 157.4 & 173.3 & 161.1
\end{array}$$

Given that the result of the hypothesis test is that there is significant evidence to reject $\mathrm { H } _ { 0 }$ at the $5 \%$ level of significance, calculate the minimum possible missing output value, $\alpha$. Give your answer correct to 1 decimal place.\\

\hfill \mbox{\textit{Edexcel S3 2014 Q4 [6]}}