| Exam Board | Edexcel |
|---|---|
| Module | S1 (Statistics 1) |
| Year | 2013 |
| Session | June |
| Marks | 11 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Measures of Location and Spread |
| Type | Direct cumulative frequency graph reading |
| Difficulty | Easy -1.3 This is a routine statistics question requiring standard procedures: reading values from a cumulative frequency graph, calculating median/quartiles from a stem-and-leaf diagram, identifying outliers using the 1.5×IQR rule, drawing a box plot, and making basic comparative statements. All techniques are direct applications of S1 syllabus content with no problem-solving or novel insight required. |
| Spec | 2.02a Interpret single variable data: tables and diagrams2.02f Measures of average and spread2.02g Calculate mean and standard deviation2.02h Recognize outliers2.02j Clean data: missing data, errors |
| Mark | (2|6 means 26) | Totals |
| 1 | 4 | (1) |
| 2 | 6 | (1) |
| 3 | 447 | (3) |
| 4 | 066778 | (6) |
| 5 | 001113677 | (9) |
| 6 | 223338 | (6) |
| 7 | 008 | (3) |
| 8 | 5 | (1) |
| 9 | 0 | (1) |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Marks | Guidance |
| 25 (allow any \(x\) where \(24 < x < 26\)) | B1 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Marks | Guidance |
| \(Q_2\) (or median or \(m\)) \(= \mathbf{51}\) | B1 | Mark (b) and (c) together BUT must see clear statement that median (or \(m\) or \(Q_2\)) = 51 and IQR = 17 |
| \(\mathbf{IQR} = 63 - 46 = \mathbf{17}\) (or \(Q_3 - Q_1 = 17\)) | M1, A1 | M1 for 2 quartiles (at least one correct) and attempt to find the difference. Must see \(63 -\) their \(46\). A1 for 17 only. [Answer only of IQR = 17 scores M1A1] |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Marks | Guidance |
| Outliers given by \(46 - 1.5 \times 17 = 20.5\) or \(63 + 1.5 \times 17 = 88.5\) | M1 | 1st M1 for correct attempt to calc at least one limit for outliers, ft their quartiles or IQR, or award for sight of 20.5 or 88.5 |
| Outlier limits are \(\mathbf{20.5}\) and \(\mathbf{88.5}\) | A1 | 1st A1 for identifying both limits of 20.5 and 88.5 |
| Box plot with whiskers to 20.5 and 88.5; outliers at 14 and 90 | M1 A1ft B1 | 2nd M1 for box with upper and lower whisker(s) with at least 2 correct values (or correct ft). 2nd A1ft for 20.5 or 26, 46, 51, 63 and 85 or 88.5 in appropriate places. B1 for only 2 outliers appropriately marked at 14 and 90. Apply \(\pm 0.5\) square accuracy for diagram. A box plot not on graph paper can only score 1st M1A1 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Marks | Guidance |
| Medians: Median for females lower than males | B1ft | 1st B1ft for one correct comment comparing median, IQR, range or skewness |
| IQR: IQR for females smaller than males. Allow "lower/higher" but not "wider" | B1ft | 2nd B1ft for second correct comment comparing median, IQR, range or skewness. Do not allow contradictory statements |
| Range: Range of females is less than males | ||
| Skewness: Male and female marks are both positively skew | In (d) ft from their diagrams (if no diagram then use their values) |
# Question 2:
## Part (a)
| Answer/Working | Marks | Guidance |
|---|---|---|
| 25 (allow any $x$ where $24 < x < 26$) | B1 | |
## Part (b)
| Answer/Working | Marks | Guidance |
|---|---|---|
| $Q_2$ (or median or $m$) $= \mathbf{51}$ | B1 | Mark (b) and (c) together BUT must see clear statement that median (or $m$ or $Q_2$) = 51 and IQR = 17 |
| $\mathbf{IQR} = 63 - 46 = \mathbf{17}$ (or $Q_3 - Q_1 = 17$) | M1, A1 | M1 for 2 quartiles (at least one correct) and attempt to find the difference. Must see $63 -$ their $46$. A1 for 17 only. [Answer only of IQR = 17 scores M1A1] |
## Part (c)
| Answer/Working | Marks | Guidance |
|---|---|---|
| Outliers given by $46 - 1.5 \times 17 = 20.5$ or $63 + 1.5 \times 17 = 88.5$ | M1 | 1st M1 for correct attempt to calc at least one limit for outliers, ft their quartiles or IQR, or award for sight of 20.5 or 88.5 |
| Outlier limits are $\mathbf{20.5}$ and $\mathbf{88.5}$ | A1 | 1st A1 for identifying both limits of 20.5 and 88.5 |
| Box plot with whiskers to 20.5 and 88.5; outliers at 14 and 90 | M1 A1ft B1 | 2nd M1 for box with upper and lower whisker(s) with at least 2 correct values (or correct ft). 2nd A1ft for 20.5 or 26, 46, 51, 63 and 85 or 88.5 in appropriate places. B1 for only 2 outliers appropriately marked at 14 and 90. **Apply $\pm 0.5$ square accuracy for diagram**. A box plot not on graph paper can only score 1st M1A1 |
## Part (d)
| Answer/Working | Marks | Guidance |
|---|---|---|
| **Medians:** Median for females lower than males | B1ft | 1st B1ft for one correct comment comparing median, IQR, range or skewness |
| **IQR:** IQR for females smaller than males. Allow "lower/higher" but not "wider" | B1ft | 2nd B1ft for second correct comment comparing median, IQR, range or skewness. Do not allow contradictory statements |
| **Range:** Range of females is less than males | | |
| **Skewness:** Male and female marks are both positively skew | | In (d) ft from their diagrams (if no diagram then use their values) |
\begin{enumerate}
\item The marks of a group of female students in a statistics test are summarised in Figure 1
\end{enumerate}
\begin{figure}[h]
\begin{center}
\includegraphics[alt={},max width=\textwidth]{6faf2dd2-a114-40b7-88ae-4a75dbfb4706-04_629_1102_342_429}
\captionsetup{labelformat=empty}
\caption{Figure 1}
\end{center}
\end{figure}
(a) Write down the mark which is exceeded by $75 \%$ of the female students.
The marks of a group of male students in the same statistics test are summarised by the stem and leaf diagram below.
\begin{center}
\begin{tabular}{|l|l|l|}
\hline
Mark & (2|6 means 26) & Totals \\
\hline
1 & 4 & (1) \\
\hline
2 & 6 & (1) \\
\hline
3 & 447 & (3) \\
\hline
4 & 066778 & (6) \\
\hline
5 & 001113677 & (9) \\
\hline
6 & 223338 & (6) \\
\hline
7 & 008 & (3) \\
\hline
8 & 5 & (1) \\
\hline
9 & 0 & (1) \\
\hline
\end{tabular}
\end{center}
(b) Find the median and interquartile range of the marks of the male students.
An outlier is a mark that is\\
either more than $1.5 \times$ interquartile range above the upper quartile or more than $1.5 \times$ interquartile range below the lower quartile.\\
(c) In the space provided on Figure 1 draw a box plot to represent the marks of the male students, indicating clearly any outliers.\\
(d) Compare and contrast the marks of the male and the female students.\\
\hfill \mbox{\textit{Edexcel S1 2013 Q2 [11]}}