Edexcel S1 2013 June — Question 3 12 marks

Exam BoardEdexcel
ModuleS1 (Statistics 1)
Year2013
SessionJune
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicConditional Probability
TypeBasic two-way table probability
DifficultyEasy -1.3 This is a straightforward S1 question testing basic probability concepts from a two-way table. Parts (a)-(c) require simple reading from the table and applying basic probability formulas (P(A), complement rule, conditional probability). Part (d) is routine Venn diagram construction, and part (e) uses the law of total probability with given percentages. All techniques are standard textbook exercises with no problem-solving insight required, making this easier than average for A-level.
Spec2.03a Mutually exclusive and independent events2.03b Probability diagrams: tree, Venn, sample space2.03c Conditional probability: using diagrams/tables2.03d Calculate conditional probability: from first principles

3. In a company the 200 employees are classified as full-time workers, part-time workers or contractors.
The table below shows the number of employees in each category and whether they walk to work or use some form of transport.
\cline { 2 - 3 } \multicolumn{1}{c|}{}WalkTransport
Full-time worker28
Part-time worker3575
Contractor3050
The events \(F , H\) and \(C\) are that an employee is a full-time worker, part-time worker or contractor respectively. Let \(W\) be the event that an employee walks to work. An employee is selected at random.
Find
  1. \(\mathrm { P } ( H )\)
  2. \(\mathrm { P } \left( [ F \cap W ] ^ { \prime } \right)\)
  3. \(\mathrm { P } ( W \mid C )\) Let \(B\) be the event that an employee uses the bus.
    Given that \(10 \%\) of full-time workers use the bus, \(30 \%\) of part-time workers use the bus and \(20 \%\) of contractors use the bus,
  4. draw a Venn diagram to represent the events \(F , H , C\) and \(B\),
  5. find the probability that a randomly selected employee uses the bus to travel to work.

Question 3:
Part (a)
AnswerMarks Guidance
\(\frac{35+75}{200} = 0.55\)M1 A1 Denominator of 200 and attempt to add \(2+8\) or \(35+75\) or \(30+50\); for 0.55 or exact equivalent fraction e.g. \(\frac{11}{20}\)
Part (b)
AnswerMarks Guidance
\(\frac{200-2}{200} = 0.99\)M1 A1 For a fully correct expression e.g. \(1-0.01\); for 0.99 or exact equivalent fraction
Part (c)
AnswerMarks Guidance
\([P(WC)] = \frac{P(W \cap C)}{P(C)} = \frac{30/200}{80/200} = \frac{30}{80} = 0.375\) M1 A1
Part (d)
AnswerMarks Guidance
Venn diagram with values: \(F\): 9, 1; \(C\): 64, 16; \(H\): 33, 77; intersections marked 0; \((0)\) between \(B\) and outer setsM1, B1 for 9,1; B1 for 77,33; B1 for 64,16 Allow diagrams with intersections between \(F\), \(C\) and \(H\) provided marked with 0; if diagram indicates extra empty regions do not treat blank as 0
Part (e)
AnswerMarks Guidance
\(\frac{1+16+33}{200} = 0.25\)M1 A1 For numerator made up of their \(1\) + their \(16\) + their \(33\) and denom of 200 and num \(< 200\); also allow sum of their probabilities (provided sum \(< 1\)); for 0.25 or exact equivalent
# Question 3:

## Part (a)
| $\frac{35+75}{200} = 0.55$ | M1 A1 | Denominator of 200 and attempt to add $2+8$ or $35+75$ or $30+50$; for 0.55 or exact equivalent fraction e.g. $\frac{11}{20}$ |

## Part (b)
| $\frac{200-2}{200} = 0.99$ | M1 A1 | For a fully correct expression e.g. $1-0.01$; for 0.99 or exact equivalent fraction |

## Part (c)
| $[P(W|C)] = \frac{P(W \cap C)}{P(C)} = \frac{30/200}{80/200} = \frac{30}{80} = 0.375$ | M1 A1 | For a correct ratio or formula and at least one correct prob; award M0 if num is $P(W) \times P(C) = \frac{67}{200} \times \frac{80}{200}$ or if num>denom; for 0.375 or 3/8 or exact equivalent |

## Part (d)
| Venn diagram with values: $F$: 9, 1; $C$: 64, 16; $H$: 33, 77; intersections marked 0; $(0)$ between $B$ and outer sets | M1, B1 for 9,1; B1 for 77,33; B1 for 64,16 | Allow diagrams with intersections between $F$, $C$ and $H$ provided marked with 0; if diagram indicates extra empty regions do not treat blank as 0 |

## Part (e)
| $\frac{1+16+33}{200} = 0.25$ | M1 A1 | For numerator made up of their $1$ + their $16$ + their $33$ and denom of 200 and num $< 200$; also allow sum of their probabilities (provided sum $< 1$); for 0.25 or exact equivalent |

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3. In a company the 200 employees are classified as full-time workers, part-time workers or contractors.\\
The table below shows the number of employees in each category and whether they walk to work or use some form of transport.

\begin{center}
\begin{tabular}{ | c | c | c | }
\cline { 2 - 3 }
\multicolumn{1}{c|}{} & Walk & Transport \\
\hline
Full-time worker & 2 & 8 \\
\hline
Part-time worker & 35 & 75 \\
\hline
Contractor & 30 & 50 \\
\hline
\end{tabular}
\end{center}

The events $F , H$ and $C$ are that an employee is a full-time worker, part-time worker or contractor respectively. Let $W$ be the event that an employee walks to work.

An employee is selected at random.\\
Find
\begin{enumerate}[label=(\alph*)]
\item $\mathrm { P } ( H )$
\item $\mathrm { P } \left( [ F \cap W ] ^ { \prime } \right)$
\item $\mathrm { P } ( W \mid C )$

Let $B$ be the event that an employee uses the bus.\\
Given that $10 \%$ of full-time workers use the bus, $30 \%$ of part-time workers use the bus and $20 \%$ of contractors use the bus,
\item draw a Venn diagram to represent the events $F , H , C$ and $B$,
\item find the probability that a randomly selected employee uses the bus to travel to work.
\end{enumerate}

\hfill \mbox{\textit{Edexcel S1 2013 Q3 [12]}}