- The weight, in grams, of beans in a tin is normally distributed with mean \(\mu\) and standard deviation 7.8
Given that \(10 \%\) of tins contain less than 200 g , find
- the value of \(\mu\)
- the percentage of tins that contain more than 225 g of beans.
The machine settings are adjusted so that the weight, in grams, of beans in a tin is normally distributed with mean 205 and standard deviation \(\sigma\).
- Given that \(98 \%\) of tins contain between 200 g and 210 g find the value of \(\sigma\).