| Exam Board | OCR |
|---|---|
| Module | Further Mechanics (Further Mechanics) |
| Year | 2019 |
| Session | June |
| Marks | 14 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | First order differential equations (integrating factor) |
| Type | Applied/modelling contexts |
| Difficulty | Standard +0.3 This is a standard Further Maths mechanics question combining Newton's second law with a first-order linear differential equation. Part (a) requires setting up the equation from given forces, part (b) involves solving using integrating factor (a routine technique at this level), and part (c) requires integration of velocity. While it's multi-step and requires careful algebra, all techniques are standard and the question provides significant scaffolding through 'show that' parts. |
| Spec | 4.10c Integrating factor: first order equations6.06a Variable force: dv/dt or v*dv/dx methods |
| Answer | Marks | Guidance |
|---|---|---|
| 5 | (a) | R k v 25kk 0.4 |
| Answer | Marks |
|---|---|
| dt dt 45 | M1 |
| Answer | Marks | Guidance |
|---|---|---|
| [2] | 3.3 | |
| 3.3 | AG | Must be clear equation has |
| Answer | Marks |
|---|---|
| 2 | M1 |
| Answer | Marks |
|---|---|
| 2 | A1 |
| Answer | Marks | Guidance |
|---|---|---|
| 5 | (b) | (ii) |
| Answer | Marks |
|---|---|
| as t | B1 |
| Answer | Marks |
|---|---|
| [3] | 3.4 |
| Answer | Marks |
|---|---|
| 3.4 | Allow the idea that v = 2.5f for large |
| Answer | Marks |
|---|---|
| See above | SC: If B0B1B0 or B0B0B0 |
| Answer | Marks | Guidance |
|---|---|---|
| 5 | (c) | dx 1 4t |
| Answer | Marks |
|---|---|
| 8 | B1 |
| Answer | Marks |
|---|---|
| [4] | 1.1 |
| Answer | Marks |
|---|---|
| 1.1 | Could be in a definite integral |
Question 5:
5 | (a) | R k v 25kk 0.4
dv dv 10f 4v
F ma f 0.4v4.5
dt dt 45 | M1
A1
[2] | 3.3
3.3 | AG | Must be clear equation has
come from NII
Alternate Method
Must include e𝑘𝑡
4 4
𝐼𝐹 = e∫ 45 d𝑡 = e45 𝑡
B1
d 4 𝑡 2 4 𝑡
(𝑣e45 )= 𝑓e45 oe
d𝑡 9
M1
4 5 4
𝑡 𝑡
𝑣e45 = 𝑓e45 +𝑐
2
5
𝑐 = 𝑢− 𝑓
2 | M1
M1
5 5 −4
𝑡
𝑣 = 𝑓+(𝑢− 𝑓e45 )→
2 2
1 −4
𝑣 = (5𝑓−(5𝑓−2𝑢)e45 𝑡 )
2 | A1
[5]
Must include e𝑘𝑡
5 | (b) | (ii) | u2.5f v increases (from u) and approaches 2.5f
as t
u2.5f v2.5f, constant
u2.5f v decreases (from u) and approaches 2.5f
as t | B1
B1
B1
[3] | 3.4
3.4
3.4 | Allow the idea that v = 2.5f for large
t, and allow technically inaccurate
statements (eg “v speeds up”)
provided that intent is clear
See above | SC: If B0B1B0 or B0B0B0
awarded. If mentions v
approaches 2.5f for cases 1
and 3 award B1 or if
mentions v increases in case
1 and v decreases in case 3
award B1
5 | (c) | dx 1 4t
5e 45 f oe
dt 2
x2.5ft 45 fe 4 4 5 t c
8
45
c f and use of t = 9 to find x
8
45 3e0.8
x f
8 | B1
*M1
Dep*
M1
A1
[4] | 1.1
3.4
1.1
1.1 | Could be in a definite integral
Substituting t = 0, x = 0 to obtain c,
45 4t 9
or x 2.5ft fe 45 with
8
0
correct use of limits
5 A particle $P$ of mass 4.5 kg is free to move along the $x$-axis. In a model of the motion it is assumed that $P$ is acted on by two forces:
\begin{itemize}
\item a constant force of magnitude $f \mathrm {~N}$ in the positive $x$ direction;
\item a resistance to motion, $R \mathrm {~N}$, whose magnitude is proportional to the speed of $P$.
\end{itemize}
At time $t$ seconds the velocity of $P$ is $v \mathrm {~ms} ^ { - 1 }$. When $t = 0 , P$ is at the origin $O$ and is moving in the positive direction with speed $u \mathrm {~ms} ^ { - 1 }$, and when $v = 5 , R = 2$.
\begin{enumerate}[label=(\alph*)]
\item Show that, according to the model, $\frac { d v } { d t } = \frac { 10 f - 4 v } { 45 }$.
\item \begin{enumerate}[label=(\roman*)]
\item By solving the differential equation in part (a), show that $\mathrm { v } = \frac { 1 } { 2 } \left( 5 \mathrm { f } - ( 5 \mathrm { f } - 2 \mathrm { u } ) \mathrm { e } ^ { - \frac { 4 } { 45 } \mathrm { t } } \right)$.
\item Describe briefly how, according to the model, the speed of $P$ varies over time in each of the following cases.
\begin{itemize}
\end{enumerate}\item $\mathrm { u } < 2.5 \mathrm { f }$
\item $\mathrm { u } = 2.5 \mathrm { f }$
\item $u > 2.5 f$
\item In the case where $\mathrm { u } = 2 \mathrm { f }$, find in terms of $f$ the exact displacement of $P$ from $O$ when $t = 9$.
\end{itemize}
\end{enumerate}
\hfill \mbox{\textit{OCR Further Mechanics 2019 Q5 [14]}}