OCR Further Mechanics 2019 June — Question 2 10 marks

Exam BoardOCR
ModuleFurther Mechanics (Further Mechanics)
Year2019
SessionJune
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDimensional Analysis
TypeFind exponents with all unknowns
DifficultyStandard +0.3 This is a straightforward dimensional analysis problem requiring students to set up and solve three simultaneous equations from matching dimensions. Part (a) is routine mechanics; part (b) is simple ratio calculation; part (c) tests conceptual understanding that dimensionless quantities cannot be determined by dimensional analysis. Easier than average as it's a standard textbook application with clear structure.
Spec6.01a Dimensions: M, L, T notation6.01b Units vs dimensions: relationship6.01c Dimensional analysis: error checking6.01d Unknown indices: using dimensions

2 A solenoid is a device formed by winding a wire tightly around a hollow cylinder so that the wire forms (approximately) circular loops along the cylinder (see diagram). \includegraphics[max width=\textwidth, alt={}, center]{9bc86277-9e6b-41f6-a2c3-94c85e7b1360-2_161_691_1681_246} When the wire carries an electrical current a magnetic field is created inside the solenoid which can cause a particle which is moving inside the solenoid to accelerate. A student is carrying out experiments on particles moving inside solenoids. His professor suggests that, for a particle of mass \(m\) moving with speed \(v\) inside a solenoid of length \(h\), the acceleration \(a\) of the particle can be modelled by a relationship of the form \(a = \mathrm { km } ^ { \alpha } \mathrm { v } ^ { \beta } \mathrm { h } ^ { \gamma }\), where \(k\) is a constant. The professor tells the student that \([ k ] = \mathrm { MLT } ^ { - 1 }\).
  1. Use dimensional analysis to find \(\alpha , \beta\) and \(\gamma\).
  2. The mass of an electron is \(9.11 \times 10 ^ { - 31 } \mathrm {~kg}\) and the mass of a proton is \(1.67 \times 10 ^ { - 27 } \mathrm {~kg}\). For an electron and a proton moving inside the same solenoid with the same speed, use the model to find the ratio of the acceleration of the electron to the acceleration of the proton. [3]
  3. The professor tells the student that \(a\) also depends on the number of turns or loops of wire, \(N\), that the solenoid has. Explain why dimensional analysis cannot be used to determine the dependence of \(a\) on \(N\). [1

Question 2:
AnswerMarks Guidance
2(a) [a] = LT2
[h] = L and [m] = M and [v] = LT1
M: 0 = 1 +  so  = 1
L: 1 = 1 +  + 
T: 2 = 1  
AnswerMarks
 = 1 and  = 1B1
B1
B1
M1
M1
A1
AnswerMarks
[6]3.3
1.2
3.3
1.1
3.4
AnswerMarks Guidance
1.1www
2(b) (9.11×10−31)−1 or (1.67×10−27)−1 oe
(9.11×10−31)−1: (1.67×10−27)−1
1.671027:9.111031
AnswerMarks
or awrt 1830 (:1)M1
M1
A1
AnswerMarks
[3]3.4
2.2a
AnswerMarks
1.11
Using a
m
Division of values or forming a ratio
Accept answers in words (eg the
acceleration of the electron is 1830
AnswerMarks
times the acceleration of the proton)Could be either way round
Reciprocals not acceptable
in final answer
AnswerMarks Guidance
2(c) Because N is a dimensionless quantity
[1]3.5b Must see ‘dimensionless’ or ‘no
dimensions’
Question 2:
2 | (a) | [a] = LT2
[h] = L and [m] = M and [v] = LT1
M: 0 = 1 +  so  = 1
L: 1 = 1 +  + 
T: 2 = 1  
 = 1 and  = 1 | B1
B1
B1
M1
M1
A1
[6] | 3.3
1.2
3.3
1.1
3.4
1.1 | www
2 | (b) | (9.11×10−31)−1 or (1.67×10−27)−1 oe
(9.11×10−31)−1: (1.67×10−27)−1
1.671027:9.111031
or awrt 1830 (:1) | M1
M1
A1
[3] | 3.4
2.2a
1.1 | 1
Using a
m
Division of values or forming a ratio
Accept answers in words (eg the
acceleration of the electron is 1830
times the acceleration of the proton) | Could be either way round
Reciprocals not acceptable
in final answer
2 | (c) | Because N is a dimensionless quantity | E1
[1] | 3.5b | Must see ‘dimensionless’ or ‘no
dimensions’
2 A solenoid is a device formed by winding a wire tightly around a hollow cylinder so that the wire forms (approximately) circular loops along the cylinder (see diagram).\\
\includegraphics[max width=\textwidth, alt={}, center]{9bc86277-9e6b-41f6-a2c3-94c85e7b1360-2_161_691_1681_246}

When the wire carries an electrical current a magnetic field is created inside the solenoid which can cause a particle which is moving inside the solenoid to accelerate.

A student is carrying out experiments on particles moving inside solenoids. His professor suggests that, for a particle of mass $m$ moving with speed $v$ inside a solenoid of length $h$, the acceleration $a$ of the particle can be modelled by a relationship of the form $a = \mathrm { km } ^ { \alpha } \mathrm { v } ^ { \beta } \mathrm { h } ^ { \gamma }$, where $k$ is a constant. The professor tells the student that $[ k ] = \mathrm { MLT } ^ { - 1 }$.
\begin{enumerate}[label=(\alph*)]
\item Use dimensional analysis to find $\alpha , \beta$ and $\gamma$.
\item The mass of an electron is $9.11 \times 10 ^ { - 31 } \mathrm {~kg}$ and the mass of a proton is $1.67 \times 10 ^ { - 27 } \mathrm {~kg}$.

For an electron and a proton moving inside the same solenoid with the same speed, use the model to find the ratio of the acceleration of the electron to the acceleration of the proton. [3]
\item The professor tells the student that $a$ also depends on the number of turns or loops of wire, $N$, that the solenoid has.

Explain why dimensional analysis cannot be used to determine the dependence of $a$ on $N$. [1
\end{enumerate}

\hfill \mbox{\textit{OCR Further Mechanics 2019 Q2 [10]}}