OCR Further Mechanics 2019 June — Question 1

Exam BoardOCR
ModuleFurther Mechanics (Further Mechanics)
Year2019
SessionJune
TopicCentre of Mass 2

1 The region bounded by the \(x\)-axis, the curve \(\mathrm { y } = \sqrt { 2 x ^ { 3 } - 15 x ^ { 2 } + 36 x - 20 }\) and the lines \(x = 1\) and \(x = 4\) is rotated through \(2 \pi\) radians about the \(x\)-axis to form a uniform solid of revolution \(R\). The centre of mass of \(R\) is the point \(G\) (see diagram).
\includegraphics[max width=\textwidth, alt={}, center]{9bc86277-9e6b-41f6-a2c3-94c85e7b1360-2_569_463_507_280}
  1. Explain why the \(y\)-coordinate of \(G\) is 0 .
  2. Find the \(x\)-coordinate of \(G\).
    \(P\) is a point on the edge of the curved surface of \(R\) where \(x = 4 . R\) is freely suspended from \(P\) and hangs in equilibrium.
  3. Find the angle between the axis of symmetry of \(R\) and the vertical.