OCR MEI Paper 1 Specimen — Question 5 4 marks

Exam BoardOCR MEI
ModulePaper 1 (Paper 1)
SessionSpecimen
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFriction
TypePractical friction scenarios
DifficultyModerate -0.3 This is a straightforward friction problem requiring resolution of forces and understanding of limiting friction. Part (a) involves basic trigonometry (100cos32°) with no problem-solving insight needed. Part (b) tests conceptual understanding that reducing the angle increases the horizontal component, thus increasing friction, but remains a standard textbook scenario requiring minimal reasoning beyond the mechanics syllabus fundamentals.
Spec3.03a Force: vector nature and diagrams3.03i Normal reaction force3.03r Friction: concept and vector form3.03u Static equilibrium: on rough surfaces

5 A woman is pulling a loaded sledge along horizontal ground. The only resistance to motion of the sledge is due to friction between it and the ground. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{ff44367e-c992-4e79-b255-5a04e0b8e21e-05_314_1024_486_356} \captionsetup{labelformat=empty} \caption{Fig. 5}
\end{figure} At first, she pulls with a force of 100 N inclined at \(32 ^ { \circ }\) to the horizontal, as shown in Fig.5, but the sledge does not move.
  1. Determine the frictional force between the ground and the sledge. Give your answer correct to 3 significant figures.
  2. Next she pulls with a force of 100 N inclined at a smaller angle to the horizontal. The sledge still does not move. Compare the frictional force in this new situation with that in part (a), justifying your answer.

Question 5(a):
AnswerMarks
Horizontal component \(= 100 \times \cos 32°\)M1 (3.3)
\(84.8\ \text{N}\)A1 (1.1)
Total: [2]
Question 5(b):
AnswerMarks
Frictional force is \(100\cos\theta\) [with \(\theta < 32°\)]M1 (3.4)
So frictional force increases. (oe)E1 (2.2a)
Total: [2]
## Question 5(a):

Horizontal component $= 100 \times \cos 32°$ | M1 (3.3) |
$84.8\ \text{N}$ | A1 (1.1) |
**Total: [2]**

---

## Question 5(b):

Frictional force is $100\cos\theta$ [with $\theta < 32°$] | M1 (3.4) |
So frictional force increases. (oe) | E1 (2.2a) |
**Total: [2]**
5 A woman is pulling a loaded sledge along horizontal ground. The only resistance to motion of the sledge is due to friction between it and the ground.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{ff44367e-c992-4e79-b255-5a04e0b8e21e-05_314_1024_486_356}
\captionsetup{labelformat=empty}
\caption{Fig. 5}
\end{center}
\end{figure}

At first, she pulls with a force of 100 N inclined at $32 ^ { \circ }$ to the horizontal, as shown in Fig.5, but the sledge does not move.
\begin{enumerate}[label=(\alph*)]
\item Determine the frictional force between the ground and the sledge.

Give your answer correct to 3 significant figures.
\item Next she pulls with a force of 100 N inclined at a smaller angle to the horizontal. The sledge still does not move.

Compare the frictional force in this new situation with that in part (a), justifying your answer.
\end{enumerate}

\hfill \mbox{\textit{OCR MEI Paper 1  Q5 [4]}}