| Exam Board | OCR MEI |
|---|---|
| Module | Paper 1 (Paper 1) |
| Session | Specimen |
| Marks | 2 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Radians, Arc Length and Sector Area |
| Type | Sector area calculation |
| Difficulty | Easy -1.2 This is a straightforward application of the sector area formula A = ½r²θ with all values given except θ. It requires only direct substitution (5 = ½×7²×θ) and simple algebraic rearrangement, making it easier than average with minimal problem-solving demand. |
| Spec | 1.05d Radians: arc length s=r*theta and sector area A=1/2 r^2 theta |
| Answer | Marks | Guidance |
|---|---|---|
| \(\text{Area} = 5 = \frac{1}{2} \times 7^2 \times \theta\) | M1 (3.1a) | Correct formula applied |
| \(\theta = \frac{10}{49} [= 0.204]\) | A1 (1.1) |
## Question 1:
$\text{Area} = 5 = \frac{1}{2} \times 7^2 \times \theta$ | M1 (3.1a) | Correct formula applied
$\theta = \frac{10}{49} [= 0.204]$ | A1 (1.1) |
**Total: [2]**
---1 Fig. 1 shows a sector of a circle of radius 7 cm . The area of the sector is $5 \mathrm {~cm} ^ { 2 }$.
\begin{figure}[h]
\begin{center}
\includegraphics[alt={},max width=\textwidth]{ff44367e-c992-4e79-b255-5a04e0b8e21e-04_222_199_621_306}
\captionsetup{labelformat=empty}
\caption{Fig. 1}
\end{center}
\end{figure}
Find the angle $\theta$ in radians.
\hfill \mbox{\textit{OCR MEI Paper 1 Q1 [2]}}