3 Solve the inequality \(| 2 x - 1 | \geq 4\).
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Question 3:
Either:
Answer Marks
Guidance
\( 2x-1
\geq 4\)
\(\Rightarrow 2x - 1 \geq 4\) M1 (1.1)
or \(\quad 2x - 1 \leq -4\) M1 (1.1)
Or:
Answer Marks
Guidance
\((2x-1)^2 \geq 16\) M1 (1.1)
M1 for sketch of \(y=(2x-1)^2\) and \(y=16\)
\(4x^2 - 4x - 15 \geq 0\)
Answer Marks
Guidance
\((2x-5)(2x+3) \geq 0\) M1 (1.1)
M1 for \(x = 2\frac{1}{2},\ -1\frac{1}{2}\)
\(\Rightarrow x \geq 2\frac{1}{2}\) A1 (1.1)
\(\Rightarrow x \leq -1\frac{1}{2}\)
Answer Marks
Guidance
\(\{x: x \leq -1\frac{1}{2}\} \cup \{x: x \geq 2\frac{1}{2}\}\) A1 (2.5)
OR \(x \geq 2\frac{1}{2}\) or \(x \leq -1\frac{1}{2}\); if final answer not in one of these forms then withhold final A1
Total: [4]
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## Question 3:
**Either:**
$|2x-1| \geq 4$
$\Rightarrow 2x - 1 \geq 4$ | M1 (1.1) |
or $\quad 2x - 1 \leq -4$ | M1 (1.1) |
**Or:**
$(2x-1)^2 \geq 16$ | M1 (1.1) | M1 for sketch of $y=(2x-1)^2$ and $y=16$
$4x^2 - 4x - 15 \geq 0$
$(2x-5)(2x+3) \geq 0$ | M1 (1.1) | M1 for $x = 2\frac{1}{2},\ -1\frac{1}{2}$
$\Rightarrow x \geq 2\frac{1}{2}$ | A1 (1.1) |
$\Rightarrow x \leq -1\frac{1}{2}$
$\{x: x \leq -1\frac{1}{2}\} \cup \{x: x \geq 2\frac{1}{2}\}$ | A1 (2.5) | OR $x \geq 2\frac{1}{2}$ or $x \leq -1\frac{1}{2}$; if final answer not in one of these forms then withhold final A1
**Total: [4]**
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3 Solve the inequality $| 2 x - 1 | \geq 4$.
\hfill \mbox{\textit{OCR MEI Paper 1 Q3 [4]}}