| Exam Board | Edexcel |
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| Module | PMT Mocks (PMT Mocks) |
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| Topic | Reciprocal Trig & Identities |
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12. a. Prove that
$$\frac { \sec ^ { 2 } x - 1 } { \sec ^ { 2 } x } \equiv \sin ^ { 2 } x$$
b. Hence solve, for \(- 360 ^ { \circ } < x < 360 ^ { \circ }\), the equation
$$\frac { \sec ^ { 2 } x - 1 } { \sec ^ { 2 } x } = \frac { \cos 2 x } { 2 }$$