Edexcel PMT Mocks — Question 1 6 marks

Exam BoardEdexcel
ModulePMT Mocks (PMT Mocks)
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComposite & Inverse Functions
TypeFind inverse function
DifficultyModerate -0.3 This is a multi-part question on rational functions requiring identification of asymptotes from a graph, stating range, and finding an inverse function. While it involves several steps, each part uses standard techniques: reading asymptotes gives a and b, the range comes from the horizontal asymptote and domain restriction, and finding the inverse of a rational function is a routine algebraic procedure taught in C3/C4. The question is slightly easier than average because the graph provides significant scaffolding for parts (a) and (b).
Spec1.02k Simplify rational expressions: factorising, cancelling, algebraic division1.02u Functions: definition and vocabulary (domain, range, mapping)1.02v Inverse and composite functions: graphs and conditions for existence

  1. The figure 1 shows part of the graph of \(y = \mathrm { f } ( x )\), where \(\mathrm { f } ( x ) = \frac { a x + 4 } { x - b } , \quad x > 2\)
\begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{f9dcb521-6aaa-4496-86e8-2dcd07838e10-02_837_1189_422_518} \captionsetup{labelformat=empty} \caption{Figure 1}
\end{figure} a. State the values of \(a\) and \(b\).
b. State the range of f.
c. Find \(\mathrm { f } ^ { - 1 } ( x )\), stating its domain.

Question 1:
Part (a): State the values of \(a\) and \(b\)
AnswerMarks Guidance
AnswerMark Guidance
\(b = 2\)B1 From vertical asymptote at \(x = 2\)
\(a = 3\)B1 From horizontal asymptote at \(y = 3\)
(2 marks)
Part (b): State the range of f
AnswerMarks Guidance
AnswerMark Guidance
\(f(x) > 3\) or \(y > 3\)B1 Either notation acceptable
(1 mark)
Part (c): Find \(f^{-1}(x)\), stating its domain
AnswerMarks Guidance
AnswerMark Guidance
Attempt to rearrange: swap \(x\) and \(y\), multiply through by \((y-2)\) and collect termsM1 Look for minimum of cross multiplying by \((x-2)\) and proceeding to form a rearranged equation
\(f^{-1}(x) = \dfrac{2x+4}{x-3}\)A1 Accept \(y = \dfrac{2x+4}{x-3}\)
Domain: \(x > 3\)A1 Must be stated
(3 marks)
## Question 1:

### Part (a): State the values of $a$ and $b$

| Answer | Mark | Guidance |
|--------|------|----------|
| $b = 2$ | B1 | From vertical asymptote at $x = 2$ |
| $a = 3$ | B1 | From horizontal asymptote at $y = 3$ |

**(2 marks)**

### Part (b): State the range of f

| Answer | Mark | Guidance |
|--------|------|----------|
| $f(x) > 3$ or $y > 3$ | B1 | Either notation acceptable |

**(1 mark)**

### Part (c): Find $f^{-1}(x)$, stating its domain

| Answer | Mark | Guidance |
|--------|------|----------|
| Attempt to rearrange: swap $x$ and $y$, multiply through by $(y-2)$ and collect terms | M1 | Look for minimum of cross multiplying by $(x-2)$ and proceeding to form a rearranged equation |
| $f^{-1}(x) = \dfrac{2x+4}{x-3}$ | A1 | Accept $y = \dfrac{2x+4}{x-3}$ |
| Domain: $x > 3$ | A1 | Must be stated |

**(3 marks)**

---
\begin{enumerate}
  \item The figure 1 shows part of the graph of $y = \mathrm { f } ( x )$, where $\mathrm { f } ( x ) = \frac { a x + 4 } { x - b } , \quad x > 2$
\end{enumerate}

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{f9dcb521-6aaa-4496-86e8-2dcd07838e10-02_837_1189_422_518}
\captionsetup{labelformat=empty}
\caption{Figure 1}
\end{center}
\end{figure}

a. State the values of $a$ and $b$.\\
b. State the range of f.\\
c. Find $\mathrm { f } ^ { - 1 } ( x )$, stating its domain.\\

\hfill \mbox{\textit{Edexcel PMT Mocks  Q1 [6]}}