| Exam Board | OCR MEI |
|---|---|
| Module | D2 (Decision Mathematics 2) |
| Year | 2011 |
| Session | June |
| Marks | 20 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Modelling and Hypothesis Testing |
| Type | Investment and asset allocation decisions |
| Difficulty | Easy -1.8 This is a straightforward decision tree problem from Decision Mathematics requiring calculation of expected monetary values at each node. While it involves multiple branches and probability calculations, it's entirely procedural with no novel problem-solving required—students follow a standard algorithm taught in D2. The arithmetic is tedious but mechanical, making this significantly easier than typical A-level pure maths questions. |
| Spec | 7.05a Critical path analysis: activity on arc networks7.05b Forward and backward pass: earliest/latest times, critical activities7.05d Latest start and earliest finish: independent and interfering float7.05e Cascade charts: scheduling and effect of delays |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Mark | Guidance |
| Stay on/leave: decision node | B1 | |
| Leave: chance node with 3 branches | B1 | |
| Good A/not good: chance node | B1 | |
| Not good: chance node with 3 branches | B1 | |
| Job/uni: decision node | B1 | |
| Job: chance node with 2 branches | B1 | |
| Uni: chance node with 4 branches | B1 | |
| Leave computation correct | B1 | cao |
| Job computation correct | B1 | cao |
| Uni computation correct | B1 | cao |
| Good comp correct | B1 | ft |
| Not good comp correct | B1 | cao |
| Good/not good correct | B1 | ft |
| Stay on value 1.78625 | B1 | cao |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Mark | Guidance |
| Utilities of outcomes correct | M1, A1 | cao |
| Computing backwards correctly | M1, A1 | ft |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Mark | Guidance |
| \(0.2 + 0.45 + 0.6 + 0.2x = 1.8\), so \(x = 2.75\) | M1, A1 | cao; equation with \(0.2x\) or division by \(0.2\) |
# Question 3:
## Parts (i) & (ii)
| Answer | Mark | Guidance |
|--------|------|----------|
| Stay on/leave: decision node | B1 | |
| Leave: chance node with 3 branches | B1 | |
| Good A/not good: chance node | B1 | |
| Not good: chance node with 3 branches | B1 | |
| Job/uni: decision node | B1 | |
| Job: chance node with 2 branches | B1 | |
| Uni: chance node with 4 branches | B1 | |
| Leave computation correct | B1 | cao |
| Job computation correct | B1 | cao |
| Uni computation correct | B1 | cao |
| Good comp correct | B1 | ft |
| Not good comp correct | B1 | cao |
| Good/not good correct | B1 | ft |
| Stay on value 1.78625 | B1 | cao |
## Part (iii)
| Answer | Mark | Guidance |
|--------|------|----------|
| Utilities of outcomes correct | M1, A1 | cao |
| Computing backwards correctly | M1, A1 | ft |
## Part (iv)
| Answer | Mark | Guidance |
|--------|------|----------|
| $0.2 + 0.45 + 0.6 + 0.2x = 1.8$, so $x = 2.75$ | M1, A1 | cao; equation with $0.2x$ or division by $0.2$ |
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3 Magnus has been researching career possibilities. He has just completed his GCSEs, and could leave school and get a good job. He estimates, discounted at today's values and given a 49 year working life, that there is a $50 \%$ chance of such a job giving him lifetime earnings of $\pounds 1.5 \mathrm {~m}$, a $30 \%$ chance of $\pounds 1.75 \mathrm {~m}$, and a $20 \%$ chance of $\pounds 2 \mathrm {~m}$.
Alternatively Magnus can stay on at school and take A levels. He estimates that, if he does so, there is a 75\% chance that he will achieve good results. If he does not achieve good results then he will still be able to take the same job as earlier, but he will have lost two years of his lifetime earnings. This will give a $50 \%$ chance of lifetime earnings of $\pounds 1.42 \mathrm {~m}$, a $30 \%$ chance of $\pounds 1.67 \mathrm {~m}$ and a $20 \%$ chance of $\pounds 1.92 \mathrm {~m}$.
If Magnus achieves good A level results then he could take a better job, which should give him discounted lifetime earnings of $\pounds 1.6 \mathrm {~m}$ with $50 \%$ probability or $\pounds 2 \mathrm {~m}$ with $50 \%$ probability. Alternatively he could go to university. This would cost Magnus another 3 years of lifetime earnings and would not guarantee him a well-paid career, since graduates sometimes choose to follow less well-paid vocations. His research shows him that graduates can expect discounted lifetime earnings of $\pounds 1 \mathrm {~m}$ with $20 \%$ probability, $\pounds 1.5 \mathrm {~m}$ with $30 \%$ probability, $\pounds 2 \mathrm {~m}$ with $30 \%$ probability, and $\pounds 3 \mathrm {~m}$ with $20 \%$ probability.\\
(i) Draw up a decision tree showing Magnus's options.\\
(ii) Using the EMV criterion, find Magnus's best course of action, and give its value.
Magnus has read that money isn't everything, and that one way to reflect this is to use a utility function and then compare expected utilities. He decides to investigate the outcome of using a function in which utility is defined to be the square root of value.\\
(iii) Using the expected utility criterion, find Magnus's best course of action, and give its utility.\\
(iv) The possibility of high earnings ( $\pounds 3 \mathrm {~m}$ ) swings Magnus's decision towards a university education. Find what value instead of $\pounds 3 \mathrm {~m}$ would make him indifferent to choosing a university education under the EMV criterion. (Do not change the probabilities.)
\hfill \mbox{\textit{OCR MEI D2 2011 Q3 [20]}}