OCR MEI D1 2015 June — Question 5 16 marks

Exam BoardOCR MEI
ModuleD1 (Decision Mathematics 1)
Year2015
SessionJune
Marks16
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCritical Path Analysis
TypeCalculate early and late times
DifficultyModerate -0.3 This is a standard critical path analysis question requiring routine application of well-defined algorithms (drawing network, forward/backward pass, identifying critical path, and resource scheduling). While multi-part with several marks, it involves no novel problem-solving—just methodical execution of textbook procedures that D1 students practice extensively.
Spec7.05a Critical path analysis: activity on arc networks7.05b Forward and backward pass: earliest/latest times, critical activities7.05c Total float: calculation and interpretation

5 The table lists activities which are involved in framing a picture. The table also lists their durations and their immediate predecessors. Except for activities C and H, each activity is undertaken by one person. Activities C and H require no people.
ActivityDuration (mins)Immediate predecessor(s)
Aselect mounting5-
Bglue picture to mounting5A
Callow mounting glue to dry20B
Dmeasure for frame5A
Eselect type of frame10A
Fcut four frame pieces5D, E
Gpin and glue frame pieces together5F
Hallow frame glue to dry20G
Icut and bevel glass30D
Jfit glass to frame5H, I
Kfit mounted picture to frame5C, J
  1. Draw an activity on arc network for these activities.
  2. Mark on your diagram the early time and the late time for each event. Give the minimum completion time and the critical activities. A picture is to be framed as quickly as possible. Two people are available to do the job.
  3. Produce a schedule to show how two people can complete the picture framing in the minimum time. To reduce the completion time an instant glue is to be used. This will reduce the time for activities C and H to 0 minutes.
  4. Produce a schedule for two people to complete the framing in the new minimum completion time, and give that time.

Question 5:
Part (i) & (ii):
AnswerMarks Guidance
AnswerMarks Guidance
Activity on arc diagram with correct structureM1 activity on arc
F & I correctly placedA1 F & I
J correctly placedA1 J
K correctly placedA1 K
Rest of activities correctA1 rest
[5]
Forward pass correctM1A1\(\checkmark\) forward pass
Backward pass correctM1A1\(\checkmark\) backward pass
Minimum completion time \(= 55\) minutesB1cao time
Critical activities \(= \) A, E, F, G, H, J, KB1cao critical activities
[6]
Part (iii):
AnswerMarks Guidance
AnswerMarks Guidance
e.g. (each cell represents 5 minutes): \(1^{st}\) person: A, E, E, F, G, \(\ldots\), J, KM1 A, E, F, G allocated OK
\(2^{nd}\) person: B, D, I, I, I, I, I, IA1 B, D, I, J, K OK
Other activities: C, C, C, C and H, H, H, H correctly timedB1 C and H correctly timed
[3]
Part (iv):
AnswerMarks Guidance
AnswerMarks Guidance
e.g. \(1^{st}\) person: A, D, I, I, I, I, I, I, J, K; \(2^{nd}\) person: B, E, E, F, GB1 a correct schedule for two people
50 minutesB1 50 minutes seen
[2]
# Question 5:

## Part (i) & (ii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Activity on arc diagram with correct structure | M1 | activity on arc |
| F & I correctly placed | A1 | F & I |
| J correctly placed | A1 | J |
| K correctly placed | A1 | K |
| Rest of activities correct | A1 | rest |
| | **[5]** | |
| Forward pass correct | M1A1$\checkmark$ | forward pass |
| Backward pass correct | M1A1$\checkmark$ | backward pass |
| Minimum completion time $= 55$ minutes | B1cao | time |
| Critical activities $= $ A, E, F, G, H, J, K | B1cao | critical activities |
| | **[6]** | |

## Part (iii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| e.g. (each cell represents 5 minutes): $1^{st}$ person: A, E, E, F, G, $\ldots$, J, K | M1 | A, E, F, G allocated OK |
| $2^{nd}$ person: B, D, I, I, I, I, I, I | A1 | B, D, I, J, K OK |
| Other activities: C, C, C, C and H, H, H, H correctly timed | B1 | C and H correctly timed |
| | **[3]** | |

## Part (iv):

| Answer | Marks | Guidance |
|--------|-------|----------|
| e.g. $1^{st}$ person: A, D, I, I, I, I, I, I, J, K; $2^{nd}$ person: B, E, E, F, G | B1 | a correct schedule for two people |
| 50 minutes | B1 | 50 minutes seen |
| | **[2]** | |

---
5 The table lists activities which are involved in framing a picture. The table also lists their durations and their immediate predecessors. Except for activities C and H, each activity is undertaken by one person. Activities C and H require no people.

\begin{center}
\begin{tabular}{|l|l|l|l|}
\hline
\multicolumn{2}{|c|}{Activity} & Duration (mins) & Immediate predecessor(s) \\
\hline
A & select mounting & 5 & - \\
\hline
B & glue picture to mounting & 5 & A \\
\hline
C & allow mounting glue to dry & 20 & B \\
\hline
D & measure for frame & 5 & A \\
\hline
E & select type of frame & 10 & A \\
\hline
F & cut four frame pieces & 5 & D, E \\
\hline
G & pin and glue frame pieces together & 5 & F \\
\hline
H & allow frame glue to dry & 20 & G \\
\hline
I & cut and bevel glass & 30 & D \\
\hline
J & fit glass to frame & 5 & H, I \\
\hline
K & fit mounted picture to frame & 5 & C, J \\
\hline
\end{tabular}
\end{center}

(i) Draw an activity on arc network for these activities.\\
(ii) Mark on your diagram the early time and the late time for each event. Give the minimum completion time and the critical activities.

A picture is to be framed as quickly as possible. Two people are available to do the job.\\
(iii) Produce a schedule to show how two people can complete the picture framing in the minimum time.

To reduce the completion time an instant glue is to be used. This will reduce the time for activities C and H to 0 minutes.\\
(iv) Produce a schedule for two people to complete the framing in the new minimum completion time, and give that time.

\hfill \mbox{\textit{OCR MEI D1 2015 Q5 [16]}}