CAIE P3 2013 November — Question 1 3 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2013
SessionNovember
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProduct & Quotient Rules
TypeShow derivative satisfies condition
DifficultyEasy -1.2 This is a straightforward application of the quotient rule to find dy/dx, followed by a simple sign analysis. The algebra is minimal, and showing the derivative is always negative requires only observing that the numerator is negative while the denominator is positive squared—a routine exercise with no problem-solving insight needed.
Spec1.07b Gradient as rate of change: dy/dx notation

1 The equation of a curve is \(y = \frac { 1 + x } { 1 + 2 x }\) for \(x > - \frac { 1 } { 2 }\). Show that the gradient of the curve is always negative.

AnswerMarks Guidance
Use correct quotient or product ruleM1
Obtain correct derivative in any formA1
Justify the given statementA1 [3]
Use correct quotient or product rule | M1 | 
Obtain correct derivative in any form | A1 | 
Justify the given statement | A1 | [3]
1 The equation of a curve is $y = \frac { 1 + x } { 1 + 2 x }$ for $x > - \frac { 1 } { 2 }$. Show that the gradient of the curve is always negative.

\hfill \mbox{\textit{CAIE P3 2013 Q1 [3]}}