CAIE P3 2010 November — Question 3 5 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2010
SessionNovember
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicAddition & Double Angle Formulae
TypeExpand compound angle then solve
DifficultyModerate -0.3 This is a straightforward compound angle question requiring expansion of cos(θ+60°) using the addition formula, rearranging to form a single trigonometric equation (likely tan θ = constant), then finding solutions in a given range. It's slightly easier than average as it follows a standard template with no conceptual surprises, though it does require careful algebraic manipulation and knowledge of the CAST diagram.
Spec1.05l Double angle formulae: and compound angle formulae1.05o Trigonometric equations: solve in given intervals

3 Solve the equation $$\cos \left( \theta + 60 ^ { \circ } \right) = 2 \sin \theta$$ giving all solutions in the interval \(0 ^ { \circ } \leqslant \theta \leqslant 360 ^ { \circ }\).

AnswerMarks
Attempt use of \(\cos(A + B)\) formula to obtain an equation in \(\cos \theta\) and \(\sin \theta\)M1
Use trig formula to obtain an equation in \(\tan \theta\) (or \(\cos \theta\), \(\sin \theta\) or \(\cot \theta\))M1
Obtain \(\tan \theta = 1/(4 + \sqrt{3})\) or equivalent (or find \(\cos \theta\), \(\sin \theta\) or \(\cot \theta\))A1
Obtain answer \(\theta = 9.9°\)A1
Obtain \(\theta = 189.9°\), and no others in the given intervalA1
[5 marks total]
[Ignore answers outside the given interval. Treat answers in radians as a misread (0.173, 3.31).]
[The other solution methods are via \(\cos \theta = \pm(4 + \sqrt{3})\sqrt{1 + (4 + \sqrt{3})^2}\) or \(\sin \theta = \pm 1/\sqrt{1 + (4 + \sqrt{3})^2}\).]
Attempt use of $\cos(A + B)$ formula to obtain an equation in $\cos \theta$ and $\sin \theta$ | M1 |
Use trig formula to obtain an equation in $\tan \theta$ (or $\cos \theta$, $\sin \theta$ or $\cot \theta$) | M1 |
Obtain $\tan \theta = 1/(4 + \sqrt{3})$ or equivalent (or find $\cos \theta$, $\sin \theta$ or $\cot \theta$) | A1 |
Obtain answer $\theta = 9.9°$ | A1 |
Obtain $\theta = 189.9°$, and no others in the given interval | A1 |
[5 marks total]

[Ignore answers outside the given interval. Treat answers in radians as a misread (0.173, 3.31).]
[The other solution methods are via $\cos \theta = \pm(4 + \sqrt{3})\sqrt{1 + (4 + \sqrt{3})^2}$ or $\sin \theta = \pm 1/\sqrt{1 + (4 + \sqrt{3})^2}$.]
3 Solve the equation

$$\cos \left( \theta + 60 ^ { \circ } \right) = 2 \sin \theta$$

giving all solutions in the interval $0 ^ { \circ } \leqslant \theta \leqslant 360 ^ { \circ }$.

\hfill \mbox{\textit{CAIE P3 2010 Q3 [5]}}