OCR FP1 2011 June — Question 9 12 marks

Exam BoardOCR
ModuleFP1 (Further Pure Mathematics 1)
Year2011
SessionJune
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicRoots of polynomials
TypeComplex roots with real coefficients
DifficultyStandard +0.3 This is a straightforward Further Maths question testing standard results about complex conjugate roots and substitution to solve a quartic. Part (i) is immediate recall, part (ii) uses Vieta's formulas with simple arithmetic, and part (iii) is a routine substitution y²=x that reduces to the original quadratic. While it's Further Maths content, it requires no novel insight—just applying well-practiced techniques in sequence.
Spec4.02g Conjugate pairs: real coefficient polynomials4.02i Quadratic equations: with complex roots

9 One root of the quadratic equation \(x ^ { 2 } + a x + b = 0\), where \(a\) and \(b\) are real, is \(16 - 30 \mathrm { i }\).
  1. Write down the other root of the quadratic equation.
  2. Find the values of \(a\) and \(b\).
  3. Use an algebraic method to solve the quartic equation \(y ^ { 4 } + a y ^ { 2 } + b = 0\).

Question 9:
Part (i):
AnswerMarks Guidance
AnswerMarks Guidance
\(16 + 30i\)B1 [1] State correct value
Part (ii):
AnswerMarks Guidance
AnswerMarks Guidance
\(a = -32\)M1, A1 Use \(a = -(\text{sum of roots})\); obtain correct answer
\(b = 1156\)M1, A1 [4] Use \(b = \text{product of roots}\); obtain correct answer
*Alternative:*M1 Substitute, expand and equate imaginary parts
A1Obtain \(a = -32\)
M1Equate real parts
A1Obtain \(b = 1156\)
Part (iii):
AnswerMarks Guidance
AnswerMarks Guidance
\(p^2 - q^2 = 16\) and \(pq = -15\)M1 Attempt to equate real and imaginary parts of \((p+iq)^2\) & \(16-30i\) or root from (ii)
A1Obtain both results c.a.o.
M1Obtain quadratic in \(p^2\) or \(q^2\)
M1Solve to obtain \(p = (\pm)5\) or \(q = (\pm)3\)
A1Obtain 2 correct answers as complex nos
\(\pm(5 \pm 3i)\)M1 Attempt at all 4 roots
A1 [7]State other two roots as complex nos
## Question 9:

### Part (i):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $16 + 30i$ | B1 **[1]** | State correct value |

### Part (ii):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $a = -32$ | M1, A1 | Use $a = -(\text{sum of roots})$; obtain correct answer |
| $b = 1156$ | M1, A1 **[4]** | Use $b = \text{product of roots}$; obtain correct answer |
| *Alternative:* | M1 | Substitute, expand and equate imaginary parts |
| | A1 | Obtain $a = -32$ |
| | M1 | Equate real parts |
| | A1 | Obtain $b = 1156$ |

### Part (iii):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $p^2 - q^2 = 16$ and $pq = -15$ | M1 | Attempt to equate real and imaginary parts of $(p+iq)^2$ & $16-30i$ or root from (ii) |
| | A1 | Obtain both results c.a.o. |
| | M1 | Obtain quadratic in $p^2$ or $q^2$ |
| | M1 | Solve to obtain $p = (\pm)5$ or $q = (\pm)3$ |
| | A1 | Obtain 2 correct answers as complex nos |
| $\pm(5 \pm 3i)$ | M1 | Attempt at all 4 roots |
| | A1 **[7]** | State other two roots as complex nos |

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9 One root of the quadratic equation $x ^ { 2 } + a x + b = 0$, where $a$ and $b$ are real, is $16 - 30 \mathrm { i }$.\\
(i) Write down the other root of the quadratic equation.\\
(ii) Find the values of $a$ and $b$.\\
(iii) Use an algebraic method to solve the quartic equation $y ^ { 4 } + a y ^ { 2 } + b = 0$.

\hfill \mbox{\textit{OCR FP1 2011 Q9 [12]}}