OCR FP1 2011 June — Question 3 3 marks

Exam BoardOCR
ModuleFP1 (Further Pure Mathematics 1)
Year2011
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMatrices
TypeConditions for unique solution
DifficultyModerate -0.5 This is a straightforward application of the determinant condition for unique solutions (det ≠ 0). Students need to form a 2×2 matrix, calculate its determinant (k² - 16), set it equal to zero, and solve to get k = ±4. While it's a Further Maths topic, it's a standard textbook exercise requiring only routine application of a well-known result with minimal algebraic manipulation.
Spec4.03h Determinant 2x2: calculation4.03l Singular/non-singular matrices

3 By using the determinant of an appropriate matrix, find the values of \(k\) for which the simultaneous equations $$\begin{aligned} & k x + 8 y = 1 \\ & 2 x + k y = 3 \end{aligned}$$ do not have a unique solution.

Question 3:
AnswerMarks Guidance
AnswerMarks Guidance
\(k^2 - 16\)B1 Obtain correct det
M1Equate their det to \(0\)
\(k = \pm 4\)A1 [3] Obtain correct answers
## Question 3:

| Answer | Marks | Guidance |
|--------|-------|----------|
| $k^2 - 16$ | B1 | Obtain correct det |
| | M1 | Equate their det to $0$ |
| $k = \pm 4$ | A1 **[3]** | Obtain correct answers |

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3 By using the determinant of an appropriate matrix, find the values of $k$ for which the simultaneous equations

$$\begin{aligned}
& k x + 8 y = 1 \\
& 2 x + k y = 3
\end{aligned}$$

do not have a unique solution.

\hfill \mbox{\textit{OCR FP1 2011 Q3 [3]}}