OCR MEI M1 2009 January — Question 3 6 marks

Exam BoardOCR MEI
ModuleM1 (Mechanics 1)
Year2009
SessionJanuary
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVectors Introduction & 2D
TypeNewton's second law with vector forces (find acceleration or force)
DifficultyModerate -0.3 This is a straightforward application of Newton's second law (F=ma) with vectors. Part (i) requires simple vector arithmetic: find resultant force from acceleration, then subtract the given force. Part (ii) is standard dot product formula for angle between vectors. Both parts are routine calculations with no conceptual challenges beyond basic mechanics and vector operations.
Spec1.10c Magnitude and direction: of vectors1.10d Vector operations: addition and scalar multiplication3.03d Newton's second law: 2D vectors

3 The resultant of the force \(\binom { - 4 } { 8 } \mathrm {~N}\) and the force \(\mathbf { F }\) gives an object of mass 6 kg an acceleration of \(\binom { 2 } { 3 } \mathrm {~ms} ^ { - 2 }\).
  1. Calculate \(\mathbf { F }\).
  2. Calculate the angle between \(\mathbf { F }\) and the vector \(\binom { 0 } { 1 }\).

3 The resultant of the force $\binom { - 4 } { 8 } \mathrm {~N}$ and the force $\mathbf { F }$ gives an object of mass 6 kg an acceleration of $\binom { 2 } { 3 } \mathrm {~ms} ^ { - 2 }$.\\
(i) Calculate $\mathbf { F }$.\\
(ii) Calculate the angle between $\mathbf { F }$ and the vector $\binom { 0 } { 1 }$.

\hfill \mbox{\textit{OCR MEI M1 2009 Q3 [6]}}