| Exam Board | OCR MEI |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2009 |
| Session | January |
| Marks | 4 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Variable acceleration (1D) |
| Type | Velocity from acceleration by integration |
| Difficulty | Moderate -0.3 This is a straightforward mechanics question requiring students to find velocity from an acceleration-time graph by calculating areas (integration). The graph appears to show simple linear segments, making area calculation routine. While it requires understanding that area under a-t graph gives change in velocity and applying this twice, these are standard M1 techniques with no conceptual surprises or complex problem-solving. |
| Spec | 3.02a Kinematics language: position, displacement, velocity, acceleration3.02b Kinematic graphs: displacement-time and velocity-time3.02c Interpret kinematic graphs: gradient and area |
2 Fig. 2 shows an acceleration-time graph modelling the motion of a particle.
\begin{figure}[h]
\begin{center}
\includegraphics[alt={},max width=\textwidth]{93a5d409-ade4-418b-9c09-620d97df97de-2_684_1070_1064_536}
\captionsetup{labelformat=empty}
\caption{Fig. 2}
\end{center}
\end{figure}
At $t = 0$ the particle has a velocity of $6 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ in the positive direction.\\
(i) Find the velocity of the particle when $t = 2$.\\
(ii) At what time is the particle travelling in the negative direction with a speed of $6 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ ?
\hfill \mbox{\textit{OCR MEI M1 2009 Q2 [4]}}