OCR MEI C1 2007 January — Question 13 12 marks

Exam BoardOCR MEI
ModuleC1 (Core Mathematics 1)
Year2007
SessionJanuary
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFactor & Remainder Theorem
TypeGiven factor, find all roots
DifficultyModerate -0.8 This is a straightforward C1 question testing routine application of factor theorem and polynomial division. Part (i) requires simple algebraic division given a known factor, part (ii) is direct substitution and expansion, and part (iii) follows immediately from understanding transformations. All steps are standard textbook exercises with no problem-solving insight required.
Spec1.02f Solve quadratic equations: including in a function of unknown1.02j Manipulate polynomials: expanding, factorising, division, factor theorem1.02w Graph transformations: simple transformations of f(x)

13 \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{7791371e-26d9-428c-8700-5121a1c6464a-4_456_387_1539_833} \captionsetup{labelformat=empty} \caption{Fig. 13}
\end{figure} Fig. 13 shows a sketch of the curve \(y = \mathrm { f } ( x )\), where \(\mathrm { f } ( x ) = x ^ { 3 } - 5 x + 2\).
  1. Use the fact that \(x = 2\) is a root of \(\mathrm { f } ( x ) = 0\) to find the exact values of the other two roots of \(\mathrm { f } ( x ) = 0\), expressing your answers as simply as possible.
  2. Show that \(\mathrm { f } ( x - 3 ) = x ^ { 3 } - 9 x ^ { 2 } + 22 x - 10\).
  3. Write down the roots of \(\mathrm { f } ( x - 3 ) = 0\).

Question 13
(i) Use the fact that \(x = 2\) is a root of \(f(x) = 0\) to find the exact values of the other two roots of \(f(x) = 0\), expressing your answers as simply as possible. [6]
M1: Divide \(f(x) = x^3 - 5x + 2\) by \((x - 2)\) using polynomial division or synthetic division
A1: Quotient is \(x^2 + 2x - 1\) (or equivalent factorisation)
M1: Set \(x^2 + 2x - 1 = 0\) and use quadratic formula
M1: Apply \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) correctly
A1: \(x = -1 + \sqrt{2}\) and \(x = -1 - \sqrt{2}\) (or equivalent simplified form)
A1: All three roots clearly identified
(ii) Show that \(f(x - 3) = x^3 - 9x^2 + 22x + 10\). [4]
M1: Substitute \(x - 3\) into \(f(x) = x^3 - 5x + 2\)
M1: Expand \((x-3)^3\) correctly
M1: Expand and simplify \(-5(x-3)\) correctly
A1: Correct final answer \(f(x - 3) = x^3 - 9x^2 + 22x + 10\)
(iii) Write down the roots of \(f(x - 3) = 0\). [2]
B1: If \(f(x - 3) = 0\) then \(f(x - 3) = 0\) means \(x - 3\) equals a root of \(f\)
A1: Roots are \(x = 5\), \(x = 2 + \sqrt{2}\), \(x = 2 - \sqrt{2}\) (or equivalent)
## Question 13

### (i) Use the fact that $x = 2$ is a root of $f(x) = 0$ to find the exact values of the other two roots of $f(x) = 0$, expressing your answers as simply as possible. [6]

M1: Divide $f(x) = x^3 - 5x + 2$ by $(x - 2)$ using polynomial division or synthetic division

A1: Quotient is $x^2 + 2x - 1$ (or equivalent factorisation)

M1: Set $x^2 + 2x - 1 = 0$ and use quadratic formula

M1: Apply $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ correctly

A1: $x = -1 + \sqrt{2}$ and $x = -1 - \sqrt{2}$ (or equivalent simplified form)

A1: All three roots clearly identified

### (ii) Show that $f(x - 3) = x^3 - 9x^2 + 22x + 10$. [4]

M1: Substitute $x - 3$ into $f(x) = x^3 - 5x + 2$

M1: Expand $(x-3)^3$ correctly

M1: Expand and simplify $-5(x-3)$ correctly

A1: Correct final answer $f(x - 3) = x^3 - 9x^2 + 22x + 10$

### (iii) Write down the roots of $f(x - 3) = 0$. [2]

B1: If $f(x - 3) = 0$ then $f(x - 3) = 0$ means $x - 3$ equals a root of $f$

A1: Roots are $x = 5$, $x = 2 + \sqrt{2}$, $x = 2 - \sqrt{2}$ (or equivalent)
13

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{7791371e-26d9-428c-8700-5121a1c6464a-4_456_387_1539_833}
\captionsetup{labelformat=empty}
\caption{Fig. 13}
\end{center}
\end{figure}

Fig. 13 shows a sketch of the curve $y = \mathrm { f } ( x )$, where $\mathrm { f } ( x ) = x ^ { 3 } - 5 x + 2$.\\
(i) Use the fact that $x = 2$ is a root of $\mathrm { f } ( x ) = 0$ to find the exact values of the other two roots of $\mathrm { f } ( x ) = 0$, expressing your answers as simply as possible.\\
(ii) Show that $\mathrm { f } ( x - 3 ) = x ^ { 3 } - 9 x ^ { 2 } + 22 x - 10$.\\
(iii) Write down the roots of $\mathrm { f } ( x - 3 ) = 0$.

\hfill \mbox{\textit{OCR MEI C1 2007 Q13 [12]}}