| Exam Board | OCR MEI |
|---|---|
| Module | C1 (Core Mathematics 1) |
| Year | 2007 |
| Session | January |
| Marks | 3 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Factor & Remainder Theorem |
| Type | Single remainder condition to find constant |
| Difficulty | Moderate -0.8 This is a straightforward application of the remainder theorem requiring only direct substitution of x=2 into the polynomial and solving a simple linear equation. It's easier than average as it involves minimal steps and tests only basic recall of the theorem with no problem-solving complexity. |
| Spec | 1.02j Manipulate polynomials: expanding, factorising, division, factor theorem |
4 When $x ^ { 3 } + k x + 5$ is divided by $x - 2$, the remainder is 3 . Use the remainder theorem to find the value of $k$.
\hfill \mbox{\textit{OCR MEI C1 2007 Q4 [3]}}